By definition, we have to:
Where,
p: linear momentum
m: mass of the object
v: object speed
Therefore, knowing the mass of an object and its speed, we have the linear momemtum of the object.
In general, it is useful to calculate the momentum of objects in conservation problems to find the velocity before or after the collision of two objects.
Answer:
The measure of an object's mass and velocity is called momentum.
d. momentum
Answer:
1.64xrad/s
Explanation:
Given:
satellite is in elliptical orbit with a period T= 7.20 x s
Mass of planet m= 7.00x kg
Satellite's angular speed ωa- = 4.987 10-5 rad/s
At aphelion, at radius Ra= 5.1 x 10^7 m
Assuming torque is zero for this system, therefore, the conservation of angular momentum can be defines as
Lp = La
Ip ωp = Ia ωa--->eq(1)
Where,
'a' represents aphelion and 'p' represents perihelion
ω represents angular velocity
and I represents the rotational inertia
Since, I= 1/2 mR²
Here R is the radius at aphelion / perihelion
m = mass of planet
eq(1)=> ωp= Ia ωa/ Ip
ωp= (1/2 m Ra² ωa) / 1/2 m Rp²
ωp= (Ra/Rp)² ωa --->eq(2)
In order to find Rp, we use : 2a= Rp + Ra
where a represents semimajor axis
with the help of Kepler's third law for elliptical orbits
a= ∛(GmT²/4π²)
a= ∛ 6.67x x 7.00x
x (7.20 x
)² / 4π²
a= 3.97 x m
2a= Rp + Ra
Rp= 2a-Ra
Rp= 2 x 3.97 x - 5.1x
Rp= 2.84 x m
Substituting all the required values in eq 2, we have
ωp= (Ra/Rp)² ωa
ωp= (5.1x /2.84 x
)² x 4.987 x
ωp= 3.224 x 4.987 x
ωp= 1.64xrad/s
Therefore, angular speed at perihelion is 1.64xrad/s