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Tcecarenko [31]
3 years ago
13

A hydrogen atom has its electron in the n = 6 level. the radius of the electron's orbit in the bohr model is 1.905 nm.

Physics
1 answer:
gayaneshka [121]3 years ago
5 0
Are there any options or is it not multiple choice.
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A car travels 90 meters north in 15 seconds. Then turns around and travels at 40 meters south in 5.0 seconds. what is the averag
Viefleur [7K]

Average velocity  =  (displacement) / (total time)

Displacement = distance and direction between
                             the starting point and the end point

The car travels 90 meters north, then 40 meters south. 
So it ends up 50 meters north of where it began. 

Displacement = 50 meters north
Total time  =  (15 + 5) = 20 seconds

Average velocity = (50 meters north) / (20 seconds)

                             =  2.5 m/s north
4 0
3 years ago
How do ionic bonds differ from covalent bonds?
8_murik_8 [283]
A.) Electrons are Shared in a covalent bond.
7 0
3 years ago
Read 2 more answers
A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.05 m/s. If the roof is pitched at
vekshin1

1) Time in the air: 0.78 s

The motion of the ball is a projectile motion, which consists of two independent motions:

- A horizontal motion with constant horizontal velocity

- A vertical motion with constant downward acceleration of

g=-9.8 m/s^2 (acceleration of gravity)

The initial vertical velocity is

u_y = u sin \theta = (3.05)(sin(-40^{\circ}))=-1.96 m/s

where the negative sign means the direction is downward.

The vertical position of the ball is given by

y(t) = h + u_y t + \frac{1}{2}gt^2

where

h = 4.50 m is the initial heigth of the ball when it starts falling down

The ball reaches the ground when y = 0, so we have:

0 = 4.50 -1.96t-4.9t^2

This is a second-order equation; solving for t, we get

t = -1.18 s

t = 0.78 s

We discard the negative solution since it has no physical meaning, so we can say that the ball spent 0.78 s in the air.

2) Horizontal distance: 1.83 m

For this second part of the problem, we just have to consider the horizontal motion of the ball.

As we said previously, the motion of the ball along the horizontal direction is a uniform motion with constant velocity, which is given by

v_x = u cos \theta = (3.05)(cos (-40.0^{\circ}))=2.34 m/s

where u = 3.05 m/s is the initial speed and \theta the angle of projection.

For a uniform motion, we can use the following relationship between distance covered and velocity:

d=v_x t

and substituting t = 0.78 s, we find the total distance travelled along the horizontal direction by the ball before reaching the ground:

d=(2.34)(0.78)=1.83 m

7 0
3 years ago
Given that the distance from the left end of the string to the first antinode is 27.5 cm , calculate the wavelength of the stand
ivolga24 [154]

Answer:

= 0.55 m

Explanation:

A standing wave is characterized by anti-nodes and nodes.

Antinodes are points on a standing wave at maximum amplitude, while nodes are points on the standing wave that are stationary and have zero amplitude.

The distance between two adjacent nodes or two adjacent anti-nodes is equivalent to half the wavelength.

Therefore, in this case the half wavelength is 27.5 cm.

Thus, wavelength = 27.5 × 2

                              = 55 cm

                             <u>= 0.55 m</u>

6 0
3 years ago
A fox runs for 12 seconds at a speed of 9.65 m/s. How much distance does it cover? Exact answer, do NOT round.
Stella [2.4K]

Answer:

115.8

Explanation:

7 0
3 years ago
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