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3 years ago

What is the cell membrane?

Chemistry

2 answers:

tankabanditka [31]3 years ago

6 0

the semipermeable membrane surrounding the cytoplasm of a cell.

valina [46]3 years ago

4 0

The semipermeable membrane surrounding the cytoplasm of a cell.

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The molar mass of NaCl is 58.44 g/mol. What is the molarity of a solution that

Sauron [17]

3:00m cu of the current in electrical engineering and electrical toques

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3 years ago

What is true when an element is oxidized? It bonds with the hydroxide ion. It loses electrons to another element. It reacts with

Mama L [17]

Answer: It loses electrons to another element.

Explanation:- Oxidation is the process in which an element loses electrons and there is an increase in the oxidation state. On losing electrons it combines with a electronegative element such as oxygen, sulphur or nitrogen etc.

$Fe\rightarrow Fe^{2+}+2e^-$

Reduction is the process in which an element gains electrons and there is a decrease in the oxidation state.

$\frac{1}{2}O_2+2e^-\rightarrow O^{2-}$

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3 years ago

Help its due soon i need to get this right to pass the class

Igoryamba

Answer:

the answer I am pretty sure is A

Explanation:

Because the way that a generator works is moving electric current around a wire and using magnets to make more energy. please tell me if I am wrong.

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3 years ago

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When a planet has the illusion of moving backwards or bouncing up and down it is exhibiting what?

Goryan [66]

Answer: It is exhibiting retrogade motion.

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3 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

Explanation:

Wavelength of the photon emitted = $\lambda =646.3 nm =646.3\times 10^{-9} m$

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

$E=\frac{hc}{\lambda }$

h = Planck's constant = $6.626\tiomes 10^{-34} Js$

c = Speed of the light = $3\times 10^8 m/s$

$E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}$

$E=3.07\times 10^{-19} J$

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

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3 years ago