1. What is a taste bud?
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Answer:
1.95*10²² molecules are in 5.50 grams of AgNO₃
Explanation:
Being the molar mass of the elements:
- Ag: 107.87 g/mole
- N: 14 g/mole
- O: 16 g/mole
then the molar mass of the compound is:
AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole
Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?
moles= 0.0324
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?
molecules=1.95*10²²
<u><em>1.95*10²² molecules are in 5.50 grams of AgNO₃</em></u>
The powder could be acetaminophen, analgesic having chemical formula
A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.
We are given:
Percentage of C = 67.31 %
Percentage of H = 6.978 %
Percentage of N = 4.617 %
Percentage of O = 21.10 %
Let the mass of the compound be 100 g. So, the percentages given are taken as mass.
Mass of C = 67.31 g
Mass of H = 6.978 g
Mass of N = 4.617 g
Mass of O = 21.10 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of carbon =
Moles of carbon =
=5.60 moles
Moles of hydrogen =
Moles of hydrogen =
=6.978 moles
Moles of nitrogen =
Moles of nitrogen =
=0.329 moles
Moles of oxygen =
Moles of oxygen =
=1.31 moles
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.
We get the ratio of C : H : N : O = 17 : 21 : 1 : 4
The empirical formula for the given compound is .
Learn more about the empirical formula here:
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