All categories

3 years ago

Determine the volume of hydrogen collected at STP and SATP, and the molar volume at STP and SATP

1 answer:

4 0

The other given data are:
Room temperature (°C) 22.0; pressure (kPa) 100.5; Water vapor pressure at 22 °C (2.60 kPa); Mass of Mg ribbon (0.05g); Volume of hydrogen gas (mL) 48.3

Vstp = 22.4 L/mol, and Vsatp = 24.8 L/mol Vstp:0 degrees Celsius and 101.325 kPa while Vsatp: 25 degrees Celsius and 100 kPa. 100.5 kPa x 760 mm Hg/101.325 kP = 753.8119911 mmHg

2HCl(g) + Mg(s) -> H2(g) + MgCl2(aq) nMg = 0.0020571899 mol nH2 = 0.0020571899 mol Wet H2 pressure = 100.5 kPa Dry H2 pressure = 97.9 kPa

So to determine the volume of hydrogen gas collected at STP: V2 = (753.8119911 mmHg)(48.3 mL)(273 K) / (295 K)(760 mmHg) = 44.33403003 mL.

Molar volume at STP: mol/L = 44.33403003 mL / 0.0020571899 mol
= 21550.77176 mL/mol
= 21.55077176 L/mol
To determine volume of hydrogen gas collected at SATP:
V2 = (100.5 kPa)(48.3 mL)(298 K) / (295K)(100kPa) = 49.03514237 mL

Molar volume at SATP: mol/L = 49.03514237 mL / 0.0020571899 mol
= 23835.98246 mL/mol
= 23.8359824 L/mol

You might be interested in

Young fronds are called____ because of how they are coiled

topjm [15]

Answer:

Fiddlehead

Explanation:

Young fronds are called Fiddleheads

because of how they are coiled

4 0

2 years ago

Read 2 more answers

When 551. mg of a certain molecular compound X are dissolved in 100 g of benzonitrile (CH,CN), the freezing point of the solutio

arsen [322]

Answer:

1.12g/mol

Explanation:

The freezing point depression of a solvent for the addition of a solute follows the equation:

ΔT = Kf*m*i

Where ΔT is change in temperature (Benzonitrile freezing point: -12.82°C; Freezing point solution: 13.4°C)

ΔT = 13.4°C - (-12.82) = 26.22°C

m is molality of the solution

Kf is freezing point depression constant of benzonitrile (5.35°Ckgmol⁻¹)

And i is Van't Hoff factor (1 for all solutes in benzonitrile)

Replacing:

26.22°C = 5.35°Ckgmol⁻¹*m*1

4.90mol/kg = molality of the compound X

As the mass of the solvent is 100g = 0.100kg:

4.9mol/kg * 0.100kg = 0.490moles

There are 0.490 moles of X in 551mg = 0.551g, the molar mass (Ratio of grams and moles) is:

0.551g / 0.490mol

= 1.12g/mol

This result has no sense but is the result by using the freezing point of the solution = 13.4°C. Has more sense a value of -13.4°C.

5 0

2 years ago

8 moles Cl to grams 3

kirill [66]

Answer: I don’t understand what your asking elaborate more

Explanation:

7 0

3 years ago

When a metal and a nonmetal exchange electrons to make a cation and an anion, respectively, they can form an ionic compound. The

mario62 [17]

Answer:

Generally, we know that ionic compounds are formed by reaction of metals and non metals and non metals form a covalent or non ionic bonds.

IONIC COMPOUDS

Iron and chlorine (FeCl2) , ( FeCl3)
Chlorine and Lithium (LiCl)
oxygen and calcium ( CaO)
Potassium and Sulphur ( K2S)

NON IONIC COMPOUNDS

Potassium and Calcium (covalent bond)
Sulphur and Bromine (covalent bond)

Explanation:

6 0

3 years ago

Strontium chloride and sodium fluoride react to form strontium fluoride and sodium chloride, according to the reaction shown.

grin007 [14]

Answer:

4.07L of a 0.110M NaF are needed

Explanation:

Based on the reaction:

SrCl₂(aq)+2NaF(aq)⟶SrF₂(s)+2NaCl(aq)

1 mole of strontium chloride react with 2 moles of NaF

361mL of 0.620M SrCl₂ solution has:

0.361L ₓ (0.620mol / L) = 0.22382 moles SrCl₂.

Moles of NaF for a complete reaction must be:

0.22382 moles SrCl₂ ₓ (2 mol NaF / 1 mol SrCl₂) = 0.44764 moles of NaF

If you have a solution of 0.110M NaF, the moles of NaF needed are:

0.44764 moles of NaF ₓ (1L / 0.110mol NaF) = 4.07L of a 0.110M NaF are needed

6 0

3 years ago

Read 2 more answers