Anode- oxidization
Cathode-reduction
Answer:
- CFJA17
- THZ561
- GJA561
- GH68
- N461
- DG56
- BSJ57
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Answer:
The molarity is: 1 M
Explanation:
We define molarity as an amount of moles in 1000ml of solution (1 liter)
500ml---------0,5 moles AlCl3
1000ml------x= (1000ml x 0,5 moles AlCl3)/500ml = 1 moles ACl3--> 1 M