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3 years ago

13

What’s your opinion on water conservation? 5 sentences

1 answer:

skad [1K]3 years ago

4 0

<u>Opinion on Water Conservation </u>

<u> Fresh water sources is always increasing because of population and industry gowth, Even though water eventually returns to Earth through the water cycle, it's not always returned to the same spot, or in the same quantity and quality. By reducing the amount of water we use, we can better protect against future drought years. Saving water can help others with needs of it </u>

<u></u>

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We have the equation for electric field E = kQ/ $d^{2}$

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to $d^{2}$

So, $\frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$E_{1}$ = 485 N/C

$d_{1}$ = 0.208 cm

$d_{2}$ = 0.620 cm

$E_{2}$ = ?

$\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}$

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At light intensity I = 3, is P a maximum

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Given:

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or

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or

$\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}$

or

$\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}$

Now for the maxima $\frac{dP}{dI}=0$

thus,

$0=\frac{-90I^2+810)}{(I^2+I+9)^2}$

or

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or

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or

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