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3 years ago

The movement of the lithospheric plates changes the number of continents on Earth. This change would be seen over

Chemistry

2 answers:

Xelga [282]3 years ago

6 0

It is c because there are many decades today.

zhenek [66]3 years ago

4 0

Answer:

Millions of years

Explanation:

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Water and oxygen gas are the products of a chemical reaction.

Darina [25.2K]

The answer is C.

H₂O₂ ----> H₂O + O₂

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3 years ago

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Why are you people eating typods??????????????????????????

Setler79 [48]

To try to get attention, it's not safe and you can get sent to the hospital. People think it's a joke, it's really not.

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3 years ago

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Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid (

Vladimir79 [104]

Answer:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

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3 years ago

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How many moles are there in 2.00 x 1023 molecules of LiOH?

Tanya [424]

Answer:

Moles de LiOH= 0.33212 Moles

Explanation:

1 Mol of LiOH -->6.022*10^23 molecules of LiOH

therefore

$2*10^{23}~molecules ~of~LiOH=\frac{2*10^{23}}{6.02*10^{23}}Moles~of#LiOH$

5 0

3 years ago

For the reaction 3ZnCO3 + 2H3PO4 —> 3H2O + 3CO2, how many miles of zinc carbonate are required to produce 3.0 mil of Zn3(PO4)

drek231 [11]

Answer:

$\boxed{ \text{9.0 mol of ZnCO$_{3}$}}$

Explanation:

(a) Balanced equation

3ZnCO₃ + 2H₃PO₄ ⟶ Zn₃(PO₄)₂ + 3H₂O + 3CO₂

(b). Calculation

You want to convert moles of Zn₃(PO₄)₂ to moles of ZnCO₃

The molar ratio is 1 mol Zn₃(PO₄)₂:3 mol ZnCO₃

$\text{Moles of ZnCO$_{3}$} =\text{3.0 mol Zn$_{3}$(PO$_{4})_{2}$ } \times \dfrac{\text{3.0 mol ZnCO$_{3}$}}{\text{1 mol Zn$_{3}$(PO$_{4}$)$_{2}$}} \\\\\\= \text{9.0 mol ZnCO$_{3}$}$

You need $\boxed{ \textbf{9.0 mol of ZnCO$_{3}$}}$ to form 3.0 mol of Zn₃(PO₄)₂.

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3 years ago