Answer:
See explanation below
Explanation:
We have a acid base reaction of HCl and KOH, both of them are in aqueous solution. Now to get the product, we need to write the reaction first:
HCl + KOH ------->
This is an acid base reaction, and when they react it forms different products.A reaction of this type it's usually a double displacement reaction. Now, How do you know it can be a double displacement?, the key is the state of the reactants. Both of them are in aqueous solution, which means that both of them are dissolved in water respectively. In water, each of these reactants can be dissociated like this, like a decomposition reaction:
For the acid:
HCl -----> H⁺ + Cl⁻
For the base:
KOH -------> K⁺ + OH⁻
So, when the reaction occurs, both reactants dissociate first into these ions. Then, they all regroup with different ions. In the case of the H⁺, it will go to the OH⁻ (Opposites attract) and the K⁺ will go to the Cl⁻.
When this happens, the reaction gets neutralized and forms the following products:
HCl + KOH --------> KCl + H₂O
Now, let's see the states of the products. In the case of KCl, is a neutralization reaction, and we have a metal with a nonmetal reacting, and when the acid and base react, the KCl will formed as a precipitate, so, this will be solid. In the case of water, this would be in liquid state. So the final reaction would be:
<h2>
HCl(aq) + KOH(aq) --------> KCl(s) + H₂O(l)</h2>
