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ololo11 [35]
3 years ago
6

Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid (

HCl) is mixed with an aqueous solution of potassium hydroxide (KOH). Indicate the physical states of the reactants and products using the abbreviations (s), (l), (g), or (aq) for solids, liquids, gases, or aqueous solutions, respectively.
Chemistry
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

ale4655 [162]3 years ago
6 0

Answer:

See explanation below

Explanation:

We have a acid base reaction of HCl and KOH, both of them are in aqueous solution. Now to get the product, we need to write the reaction first:

HCl + KOH ------->

This is an acid base reaction, and when they react it forms different products.A reaction of this type it's usually a double displacement reaction. Now, How do you know it can be a double displacement?, the key is the state of the reactants. Both of them are in aqueous solution, which means that both of them are dissolved in water respectively. In water, each of these reactants can be dissociated like this, like a decomposition reaction:

For the acid:

HCl -----> H⁺ + Cl⁻

For the base:

KOH -------> K⁺ + OH⁻

So, when the reaction occurs, both reactants dissociate first into these ions. Then, they all regroup with different ions. In the case of the H⁺, it will go to the OH⁻ (Opposites attract) and the K⁺ will go to the Cl⁻.

When this happens, the reaction gets neutralized and forms the following products:

HCl + KOH --------> KCl + H₂O

Now, let's see the states of the products. In the case of KCl, is a neutralization reaction, and we have a metal with a nonmetal reacting, and when the acid and base react, the KCl will formed as a precipitate, so, this will be solid. In the case of water, this would be in liquid state. So the final reaction would be:

<h2>HCl(aq) + KOH(aq) --------> KCl(s) + H₂O(l)</h2>
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Sophie [7]

Answer:

The value of W is 5.602 kJ, Q is -70.6 kJ, change in U is -65 kJ, and change in H is -70.3 kJ.

Explanation:

Based on the given information, the mass of CH3OH given is 64 grams, which is condensed isothermally and reversibly to liquid at 64 degrees C. The given standard enthalpy of vaporization of methanol at 64 degrees C is 35.3 kJ per mole.

The moles of CH3OH can be determined by using the formula,  

Moles = Mass / Molar mass

= 64.0 grams / 32.0 grams per mole

= 2 mol

The amount of energy given by the process of condensation is,  

ΔH = 2 mol × 35.3 kJ/mol = 70.6 kJ

In condensation heat is given off, thus, it is an exothermic process, hence, q will be -70.6 kJ

The work or W can be calculated by using the formula,  

W = -P ΔV

Let us first find the volume of 2.0 mole gas at 64 °C, or 64 + 273 = 337 K,  

PV = nRT

V = nRT/P

= 2 mol × 0.08206 L atm per mol K × 337 K/1 atm

= 55.3 L

As the liquid condenses in the process, the change in volume would be negligible. So, the volume change will be -55.3 L

W = - 1 atm × - 55.3 L

W = 55.3 L.atm

W = 55.3 L.atm × 101.3 J/1 L atm = 5602 J

W = 5602 × 1 kJ / 1000 J = 5.602 kJ

W = 5.602 kJ

Now U can be calculated using the formula,  

U = q + W

= -70.6 kJ + 5.602 kJ

= -65. kJ

Thus, q = -70.6 kJ, W = 5.602 kJ, U = -65 kJ, and ΔH = -70.3 kJ.  

4 0
3 years ago
The atomic number is the same as the number of ________.
Zanzabum

Answer:

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Explanation:

(happy to help)

5 0
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In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
Alla [95]

The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

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Explanation:

Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

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So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

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romanna [79]

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Explanation:

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JulijaS [17]

Answer:

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Explanation:

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Please see attached photo on how to arrive at the answer.

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