Answer:
-0.383 m
Explanation:
Diameter of cylinder = 4m therefore r = 2
height of cylinder ( H ) = 4 m
specific gravity = 0.6 ( assumed )
depth of immersion = 'h'
<u>Determine the metacentric height </u>
weight of cylinder in water = water displaced
= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h
= 0.6 * 4 = h
∴ h = 2.4 m
hence the depth of center of buoyancy from free space = h /2 = 1.2 m
The metacentric height can be calculated using the formula below
Gm = Io / Vsubmerged - BG
attached below is the remaining solution
Answer:
Downwards
Explanation:
Using Fleming's right hand rule, where the middle finger represents the negative charge moving in the south to north direction, the fore finger represents the magnetic field which points in the east to west direction.
If we are to follow this orientation and place the thumb, middle finger and fore-finger at right angles to each other, the thumb represents the direction of the magnetic force on the charge.
In this case, the magnetic force points downwards after setting the other orientations of the magnetic field and the negative charge's direction.
Answer:
Explanation:
The wheel and falling student will have common acceleration .
For rotational motion of wheel
Tx r = I α , T is tension in the crank , α is angular acceleration of wheel , I is moment of inertia , r is radius of the wheel.
= I a / r
T = I a / r²
For motion of student
Mg - T = Ma , M is mass of the wheel.
Mg - I a / r² = Ma
Mg = Ma +I a / r²
Mg = (M +I / r²)a
a = Mg / (M +I / r²)
= 51 x 9.8 / ( 51 + 9.6 / .3² )
499.8 / (51+ 106.67 )
= 499.8 / 157.67
= 3.17 m / s².
If time t is taken to fall by 12 m
12 = 1/2 a t²
24 / a = t²
24 / 3.17 =t²
t²= 7.57
t = 2.75 s
velocity to reach sidewalk
v = u + at
= 3.17 x 2.75
= 8.72 m / s
Answer:
1.5 u
Explanation:
The range equation is:
R = u² sin(2θ) / g
When u = v, R = 2.25 R.
2.25 R = v² sin(2θ) / g
2.25 u² sin(2θ) / g = v² sin(2θ) / g
2.25 u² = v²
1.5 u = v
Answer:
Bones make sure the arms structure is stable while the muscle is the one actively moving it and carrying out actions.
