The speed of the block when the compression is 15 cm is 9.85 m/s.
The given parameters;
- <em>mass of the block, m = 2.4 kg</em>
- <em>height of the block, h = 5 m</em>
- <em>compression of the spring, x = 25 cm = 0.25 m</em>
The spring constant is calculated as follows;
The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;
Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.
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Answer:
A = 4.6 [m²]
Explanation:
The area of a circle can be calculated by means of the following equation.
where:
A = area [m²]
D = diameter = 2.42 [m]
Now replacing:
![A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%2A%282.42%29%5E%7B2%7D%20%5C%5CA%20%3D%204.6%20%5Bm%5E%7B2%7D%20%5D)
Yes D is definitely the answer
<em>V</em><em>=</em><em>I×</em><em>R</em>
<em>V</em><em>=</em><em>0</em><em>.</em><em>0</em><em>2</em><em>5</em><em>×</em><em>3</em><em>6</em>
<em>V</em><em>=</em><em>0</em><em>.</em><em>9</em><em> </em><em>sa</em><em>me</em><em> </em><em>as</em><em> </em><em>0</em><em>.</em><em>9</em><em>0</em>
Answer:
A. 58.8m/s
Explanation:
The acceleration due to gravity is 9.8 m/s², so the velocity after 6 seconds is ...
v = at
v = (9.8 m/s²)(6 s) = 58.8 m/s
