Answer:
Magnetic field, B = 0.23 T
Explanation:
Given that,
Length of the copper rod, L = 0.49 m
Mass of the copper rod, m = 0.15 kg
Current in rod, I = 13 A (in +ve y direction)
When the rod is placed in magnetic field, the magnetic force is balanced by its weight such that :
So, the magnitude of the minimum magnetic field needed to levitate the rod is 0.23 T.
Answer:
the final pressure of the gas is 60 kPa.
Explanation:
Given;
initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa
initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k
final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K
Let the final pressure of the gas = P₂
Apply pressure law;
Therefore, the final pressure of the gas is 60 kPa.
3.86 m/s^2 is the value of gravity on this large, but low-density, world.
given :
Kepler-12b
diameter= 1.7 times of Jupiter (R_Jupiter = 6.99 × 10^7 m),
mass = 0.43 Jupiter (M_Jupiter = 1.90 × 10^27 kg ).
g = GM/r^2
g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2
g = 3.859 ~ 3.86 m/s^2
Gravity, also referred to as gravitation, is the unchanging force of attraction that binds all matter together in mechanics. It is by far the weakest known force in nature, so it has no effect on determining the internal properties of common matter.
On Earth, everything has weight, or a gravitational pull that is imposed by the planet's mass and proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience. At the surface of the Earth, gravity accelerates at a rate of about 9.8 meters per second. As a result, an object's speed increases during free fall by about 9.8 meters per second. At the Moon's surface, a freely falling body accelerates to about 1.6 m/s2.
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The formula without numbers is
do the initial velocity would be
8.1 m/s
and the acceleration would be
2.9 m/s^2
Answer:
k = 22.05 N/m
Explanation:
The potential energy of the mass is converted into potential energy of the spring.
Given:
mass m = 0.27 kg
gravitational constant g = 9.8 m/s²
distance falling/ stretching of spring h = 0.24 m
Solving for k:
