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liraira [26]
3 years ago
10

What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31

seconds?
Explain how you got your answer.
Physics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

F = 0.483 N

Explanation:

Initial momentum, P_i= 7\ kg-m/s

Final momentum, P_f= 22\ kg-m/s

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

\text{Change in momentum}=F\times t

F is force

P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N

So, the force is 0.483 N.

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Two objects of same material are travelling near you. Object A is a 1.9 kg mass traveling 8 m/s; object B is a 2 kg mass traveli
Alex73 [517]

To determine the object which could give the greatest impact we will apply the concept of momentum. The object that has the highest momentum will be the object that will impact the strongest. Our values are

Mass of Object A

m_A=1.9 kg

Velocity of object A

v_A=8ms

Mass of object B

m_B=2 kg

Velocity of object B

v_B=5ms

The general formula for momentum is the product between mass and velocity, then

p = mv

For each object we have then,

p_A=m_Av_A=1.9 kg(8ms)=15.2kg \cdot m/s

p_B=m_Bv_B=2 kg(5ms)=10kg \cdot m/s

Since the momentum of object A is greater than that of object B, then object A will make you feel force upon impact.

3 0
3 years ago
How is it that even light precipitation can still cause the collection of large amounts of water.
Firdavs [7]

Answer:

the heat of the light.

Explanation:

no matter the light, there's always heat being produced from it. and heat makes liuqid rise

4 0
3 years ago
a ball is dropped from rest at a height of 89m above the ground. (a)what is it's speed just before it hits the ground? (b) how l
kykrilka [37]

Answer:

(a) 41.75m/s

(b) 4.26s

Explanation:

Let:

 Distance, D = 89m

 Gravity, g = 9.8 m/s^{2}

Initial Velocity, u = 0m/s

Final Velocity, v = ?

Time Taken, t = ?

With the distance formula, which is

D = ut + \frac{1}{2} gt^2

and by substituting what we already know, we have:

89 = \frac{1}{2}×9.8×t^{2}

With the equation above, we can solve for t:

t=\sqrt{\frac{89(2)}{9.8}} \\t=\sqrt{\frac{178}{9.8} } \\t=\sqrt{18.16} \\t=4.26 seconds

Now that we have solved t, we can use the following velocity formula to solve for v:

v = u + at, where a is also equals to g, so we have

v = u + gt

By substituting u = 0, g = 9.8, and t = 4.26,

We have:

v = 0 + 9.8(4.26)\\v = 41.75m/s

4 0
3 years ago
38. You are fishing and catch a fish with a mass of
adoni [48]

Answer:

1.7333333m/s²

Explanation:

Tension of the line = the weight + force from pulling up the fish

30N = mg + ma

30 = (6)(9.8) + (6)a

10.4 = 6a

∴ a = 1.7333333m/s²

6 0
2 years ago
An object moves along the x axis. The graph shows it’s position x as a function of time t. Find the average velocity of the obje
nadezda [96]
Question is from B to C

Answer: (b) 1.5m/s

x1=3m, x2=9m
t1=1s, t2=5s
Displacement, ∆x=(9-3)m=6m
Time elapsed, ∆t=(5-1)s=4s

So average velocity v =∆x/∆t=6/4=1.5m/s
6 0
2 years ago
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