Question

What is the force of a lead ball that starts with a momentum of 7 kg*m/s and end with a momentum of 22 kg*m/s over a time of 31 seconds?
Explain how you got your answer.

Answer 1

Answer:

F = 0.483 N

Explanation:

Initial momentum, $P_i= 7\ kg-m/s$

Final momentum, $P_f= 22\ kg-m/s$

Time, t = 31 s

We need to find the force of a lead ball. We can use here the impulse momentum theorem.

$\text{Change in momentum}=F\times t$

F is force

$P_f-P_i=Ft\\\\F=\dfrac{P_f-P_i}{t}\\\\F=\dfrac{22-7}{31}\\\\F=0.483\ N$

So, the force is 0.483 N.