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3 years ago

Explain how the global sea surface temperature is affected by solar activity.

1 answer:

8 0

The higher the solar activity, and the hotter it is, the more the oceans heat up and water evaporates into the atmosphere. High amounts of water vapor causes things like hurricanes. However, oceans have a high absorption rate of heat so they can absorb a lot of it without heating up the atmosphere, which is pretty good or else the Earth would overheat.

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A turntable that spins at a constant 80.0 rpmrpm takes 3.50 ss to reach this angular speed after it is turned on. Find its angul

Veronika [31]

Answer:

The angular acceleration is <u>2.39 rad/s²</u>.

The number of degrees it rotates is <u>841.68 degrees</u>.

Explanation:

Given:

Initial angular speed (ω₀) = 0 rad/s

Final angular speed in rpm (N) = 80.0 rpm

Time taken (t) = 3.50 s

First, let us determine the final angular speed in radians per second.

We know that,

$\omega=\frac{2\pi N}{60}\ rad/s$

Plug in the values and find the final angular speed, 'ω'. This gives,

$\omega=\frac{2\pi\times 80.0}{60}=8.38\ rad/s$

Now, using equation of motion for rotational motion, we have:

$\omega=\omega_0+\alpha t\\\\\alpha\to angular\ acceleration$

Plug in the given values and solve for α. This gives,

$8.38=0+\alpha \times 3.50\\\\\alpha=\frac{8.38}{3.50}=2.39\ rad/s^2$

Therefore, the angular acceleration is 2.39 rad/s².

Now, again using rotational equation of motion relating angular displacement, we have:

$\omega^2=\omega_0^2+2\alpha\theta\\\\\theta=\frac{\omega^2-\omega_0^2}{2\alpha }$

Plug in the given values and solve for 'θ'. This gives,

$\theta=\frac{(8.38)^2-0}{2\times 2.39}\\\\\theta=\frac{70.2244}{4.78}=14.69\ rad$

Convert radians to degrees using the conversion factor. This gives,

π radians = 180°

So, 1 radian =( 180 ÷ π ) degrees

Therefore, $14.69\ rad=14.69\times (\frac{180}{\pi})=841.68^\circ$

So, the number of degrees it rotates is 841.68 degrees.

3 0

3 years ago

One man wanted to weigh the air. He blew a balloon and weighed it. Then he blew air out of the balloon and weighed again. The we

raketka [301]

Answer:

Because there's buoyancy force

Explanation:

What is wrong here is that he assumes that gravity is the only force affecting the weight of the balloon on the scale here. In reality there's also buoyancy force which lifts the full blown balloon upwards.

A better type of container would be an air tank where its volume does not change when it's empty and when it's full of air.

6 0

3 years ago

Blue to gray in color and reaching up to 10 feet (3.05 meters) in length and 220 pounds (99.8 kilograms) in weight, the sailfish

vagabundo [1.1K]

Answer:

the distance traveled by the fish is 3648 m

Explanation:

In general, animals have a small period of acceleration, which we will despise after which they travel at a constant speed so we can use the kinematic equations in uniform motion

We reduce the units to System SI

t = 2 min (60s / 1 min) = 120 s

Calculate

V = x / t

x= V t

x = 30.4 120

x = 3648 m

This is the distance traveled by the fish

6 0

3 years ago

Question 3 Please, i need help! Thank you

Tom [10]

I don't know this 1 I'm sorry I can't help you

4 0

3 years ago

A ball rolls down the hill which has a vertical height of 15 m. Ignoring friction what would be the gravitational potential ener

trasher [3.6K]

a) Potential energy: 147 m [J]

The gravitational potential energy of an object is given by

$U=mgh$

where

m is its mass

$g=9.8 m/s^2$ is the acceleration of gravity

h is the height of the object above the ground

In this problem,

h = 15 m

We call 'm' the mass of the ball, since we don't know it

So, the potential energy of the ball at the top of the hill is

$U=(m)(9.8)(15)=147 m$ (J)

b) Velocity of the ball at the bottom of the hill: 17.1 m/s

According to the law of conservation of energy, in absence of friction all the potential energy of the ball is converted into kinetic energy as the ball reaches the bottom of the hill. Therefore we can write:

$U=K=\frac{1}{2}mv^2$

where

v is the final velocity of the ball

We know from part a) that

U = 147 m

Substituting into the equation above,

$147 m = \frac{1}{2}mv^2$

And re-arranging for v, we find the velocity:

$v=\sqrt{2\cdot 147}=17.1 m/s$

5 0

3 years ago