The answer is C) a rolling bowling ball because kinetic energy is the energy of movement and potential energy is the energies of the others, since there are not in movement. i hope this helps.
The answer is mass and acceleration
Answer:
Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from
The answer to the question is
The speed
of the electron when it is 10.0 cm from charge Q₁
= 7.53×10⁶ m/s
Explanation:
To solve the question we have
Q₁ = 3.45 nC = 3.45 × 10⁻⁹C
Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C
2·d = 50.0 cm
a = 10.0 cm
q = -1.6×10⁻¹⁹C
Also initial kinetic energy = 0 and
Initial electric potential energy = 
Final kinetic energy due to motion = 0.5·m·v²
Final electric potential energy = 
From the energy conservation principle we have

Solving for v gives

where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg
gives v =7528188.32769 m/s or 7.53×10⁶ m/s
= 7.53×10⁶ m/s
There are 8 electrons in the third energy level of Calcium atom.
Peak value is what we say to the maximum value of the signal..
or rms value..root mean square value