3 years ago

Ten seconds after starting from rest, a car is moving at 40 m/s. what is the car's acceleration in meters per second per second?

Physics

1 answer:

Rudik [331]3 years ago

8 0

Acceleration= 40-0/10
= 4ms-2

You might be interested in

How far from the lens must the film in a camera be, if the lens has a 35.0 mm focal length and is being used to photograph a flo

Lemur [1.5K]

Answer:

The film in a camera be is placed at a distance of 3.67 cm.

Explanation:

Given that,

Focal length of the lens, f = +35 mm = +3.5 cm

Object distance of the flower, u = -75 cm

Using lens formula to find the distance from the lens must the film in a camera be. Using lens formula as :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(3.5)}+\dfrac{1}{(-75)}\\\\v=3.67\ cm$

So, the film in a camera be is placed at a distance of 3.67 cm.

3 0

3 years ago

Two Forces are exerted on an Object In a Vertical Direction: A 20N force downwards, and 10 N force upwards. The mass of the obje

SVEN [57.7K]

When you add up (20N down) and (10N up),
you get a sum of (10N down).

The mass of the object has no effect on the forces.

Now ... I see 5 points for the answer.
Where are the other 25 coming from ?

6 0

4 years ago

You were driving your car to UTD at a speed of 35 miles per hour. You stopped at the FloydCampbell intersection with the signal

ser-zykov [4K]

Answer:

green light have high energy

Explanation:

We have given the wavelength of the red light $\lambda =6.45\times 10^{-5}cm=6.45\times 10^{-7}m$

Speed of the light $c=3\times 106{8}m/sec$

The energy of the signal is given by $E=h\nu =h\frac{c}{\lambda }=\frac{6.67\times 10^{-34}\times 3\times 10^{8}}{6.45\times 10^{-7}}=3.1023\times 10^{-15}j$