Answer:
Explanation:
Time taken by stone to cover horizontal distance
where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81
= 0.654654 seconds
t=0.65 s
Velocity, v= distance/time
v=10/0.65= 15.27525 m/s
v=15.3 m/s
where r is radius of circle, substituting r with 1.1m
Therefore, centripetal acceleration is
Answer: Macroscoptic Output
Explanation:
Answers to the rest:
1. B) macroscopic outputs.
2.A) a microscopic change creating a macroscopic output
3.B) Because the energy levels of the electrons in different metals are usually not the same, different metals usually emit different colors of visible light.
4.A) Heat is applied to a solid, causing its molecules to move quickly.
5.A) strontium, sodium, copper, potassium
Answer:
Δp = 0.05 p
Explanation:
The moment is
p = m v
The uncertainty of the moment is
Δp = dp/dm Δm + dp/dv Δv
Like the uncertainty in the mass is zero
Δm = 0
ΔP = m Δv
We divide for the moment
Δp / p = Δv / v
They do not indicate that Δv / v = 0.05
Δp / p = 0.05
Δp = 0.05 p
In the case of a system consisting of two cars
p = m₁ v₁ + m₂ v₂
Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂
Δp = m₁ Δv₁ + m₂ Δv₂
Δv₁ / v₁ = 0.05
Δv₁ = 0.05 v₁
Δv₂ / v₂ = 0.05
Δv₂ = 0.05 v₂
We replace
Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂
Δp = 0.05 p
Answer:
A. Workdone by helium, W = -1.829KJ
B. Internal energy, DE = 25.271KJ
Explanation:
Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,
W = -P*DV
Where P is the pressure in pascal
DV is the change in volume in m3
DV = Vfinal - Vinitial
= 23.70 - 5.30
= 18.4L
W = -(0.981 * 18.4)
= -18.0504L.atm
Converting L.atm to joule,
= -18.0504 * 101.325
= -1828.97J
= -1.829KJ
If the system loses heat, Q the rection occurring is Exothermic.
Heat is the transfer of energy from one system to another.
Q = mcDT
Where m is the mass of the system
C is the specific heat capacity
Q = 27.20KJ
Internal energy is the summation of the heat supplied to a system and the workdone by the system
DE = Q + W
DE = 27.10 + (-1.829)
= 25.27KJ
Increase the frequency, intensity would increase muscle mass and the other two wouldn't help improve anything
