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3 years ago

Please solve this Find H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer:

m^2+m+1

Step-by-step explanation:

m^3 - 1= (m-1)(m^2+m+1)
m^4 + m^2 + 1= m^4+2m^2+1 - m^2= (m^2+1)^2 -m^2= (m^2+m+1)(m^2-m+1)
m^2+ m + 1

HCF= m^2+m+1 which is the factor of all three polynomials

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Please solve this Find H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1​

Please solve this Find H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1