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Travka [436]
3 years ago
12

Please answer this question !! Will give brainliest !

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer & Step-by-step explanation:

In order to find the y-intercept of this equation, we must turn this equation into a slope-intercept equation. The equation for slope-intercept form is <em>y=mx+b. </em>We can do this by using these steps. Our goal is to get y by itself on one side.

6x - 2y - 9 = 0

Step 1: Add 9 on both sides of the equation.

6x - 2y = 9

Step 2: Subtract 6x on both sides of the equation. Once you subtract, make sure you put the -6x in front of 9 so we are following the rules of variables and exponents.

-2y = -6x + 9

Step 3: Divide -2 on both sides of the equation.

y = 3x - \frac{9}{2}

So, the y-intercept is -\frac{9}{2}

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6y−3(4/3y−2) Simplified please?
Hitman42 [59]

Answer:

6(3y2−2y−2)3y−2

Step-by-step explanation:

5 0
2 years ago
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What's -0.25 as a fraction
sattari [20]

Answer:

0.25 is a quarter so 1/4

then -1/4

5 0
3 years ago
What is the perimeter of the trapezoid? In unit
Korolek [52]

Answer:

20 units

Step-by-step explanation:

the perimeter = 7+4+4+5 = 20 units

5 0
3 years ago
Determine the mean, median, and more for the given data in each graph.
77julia77 [94]
5 is you median
4 is your mean
6 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
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