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frez [133]
3 years ago
13

Can someone turn 2,724.7 into a scientific notation?

Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Answer:

2.7247 x 10^3

Step-by-step explanation:

Move the decimal as many spaces to the left until it is behind the first number.

Count how many spaces you moved.

Put that number as the power of x 10^?

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Patulong naman po. pass sa di marunong
Anna35 [415]

Answer:

Bạn không tử tế :) Đó là một trò đùa

Step-by-step explanation:

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4 0
2 years ago
Pls help cause idk how to do this?!!?
tatiyna
U first start of with writing the numbers from small to greatest so it will be 45,53,53,54,60,62,63,67,68 after that your min will be your smallest, 45 and your Max is 68 than for you mid you start off at both ends with your finger ( if needed) to get your middle which in this case, it’s 60. Now for your Q1 u do the exact same thing for mid but instead of you start from 45 to 60 which gets u to 53 as ur Q1. Finally for your Q3 you you starting off at 60 and ending at 68 and doing the same thing again ur Q3 will be 63.
4 0
2 years ago
Please help me with both problems thank you so much!!
motikmotik
The one on the left is -5/6
The one on the right is 1/21
6 0
2 years ago
Read 2 more answers
3 hundred thousand 3 thousand 8 hundred 4 tens
alekssr [168]

Answer:

3384

Step-by-step explanation:

3 0
2 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
2 years ago
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