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mamaluj [8]
2 years ago
12

Would be grateful if someone could show the process for solving this problem.

Chemistry
1 answer:
In-s [12.5K]2 years ago
4 0
I don’t know i’m trying to get some points
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What do a mole of magnesium (Mg) and a mole of iron (Fe) have in common? their number of atoms their number of molecules their n
-Dominant- [34]
It has the same number of atoms
3 0
3 years ago
Chemically stable than they would
Sergio [31]

Answer:C

Explanation:

8 0
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What is adhesion and thanks?
SVETLANKA909090 [29]

adhesion refers to the tendency of unlike molecules to bond with one another

6 0
3 years ago
According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams
Alexxandr [17]

<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For KOH:</u>

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

KHSO_4+KOH\rightarrow K_2SO_4+H_2O

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = \frac{1}{1}\times 0.424=0.424moles of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0
3 years ago
Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge
zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

brainly.com/question/14044066

#SPJ1

5 0
2 years ago
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