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2 years ago

Would be grateful if someone could show the process for solving this problem.

Chemistry

1 answer:

In-s [12.5K]2 years ago

4 0

I don’t know i’m trying to get some points

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Which of the following is a synthetic organic material?

Rudik [331]

The answer is: Plastic
Plastic is the result of the addition polymerization of poly(alkenes). Thus plastic is a synthetic organic material.

Hope it helped!

4 0

3 years ago

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How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)

Vanyuwa [196]

Answer:

250000 μL

Explanation:

If 1 L = 1000 mL

Then X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if 1 μL = 10⁻⁶ L

then X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶ =250000 μL

4 0

3 years ago

What does it mean for heat to be transferred by radiation?

iris [78.8K]

Answer:

Here's what I get

Explanation:

It means that the heat comes directly at you without relying on any material to conduct it.

For example, you feel the heat from a campfire even if the wind is blowing crosswise to you and the fire.

5 0

3 years ago

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

hoa [83]

The actual yield is 43 g Cl₂.

The <em>limiting reactant was MnO₂</em> because it gave the smaller mass of Cl₂.

∴ The <em>theoretical yield</em> is 60.25 g Cl₂.

% yield = actual yield/theoretical yield × 100 %

Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g

8 0

3 years ago

According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams

e-lub [12.9K]

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.

Unsaturated solution has solute in lower proportions than required to form a saturated solution.

Supersaturated solution has solute in amounts greater than a saturated solution.

We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.

The solubility of KI at 10 $^{0}C$ is 136 g/ 100 mL water

The solubility of $KNO_{3}$ at $10^{0}C$ is 21 g/100 mL water.

The solubility of $NaNO_{3}$ at $10^{0}C$ is 80 g/100 mL water.

The solubility of NaCl at $10^{0}C$ is 38 g/ 100 mL water.

So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at $10^{0}C$ .So, if we have 80g KI/ 100mL water it would be an unsaturated solution.

4 0

3 years ago

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