Answer:
40 grams of 13% alcohol solution and 10 grams of 18% alcohol solution.
Step-by-step explanation:
13%(x) + 18%(50-x) = 14%*50g Multiply them all
0.13x + (9-0.18x) = 7
0.13x-0.18x + 9 = 7 Simplify the equation and subtract 0.13x from 0.18x
9-0.05x = 7 Add 0.05x to each side
9 = 7+0.05x Subtract 7 from both sides
0.05x = 2 Multiply each side by 100
5x = 200 Divide both sides by 5
x = 40
50 - 40 = 10
40 grams and 10 grams
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Using the Quadratic Function, Such Means x = - b + or - the square root of - 4 a c over 2 a.
After you do it you would get the answer :
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Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
