(2x²)³/6x²=(2³)(x²ˣ³) / 6x²=8x⁶/6x²=4x⁴/3
Answer: 4x⁴/3
Answer: -4 is the answer
Step-by-step explanation: google caculator
Answer:....
Step-by-step explanation:
first we need to find the base of the triangle, so the total is 20, they also give us 12, so we subtract 20-12=8 now divide. 8/2=4. Now we use the 4 and the 60. We use SOH-CAH-TOA, they give us the base now we need to find AB which is the hypotenuse. So we take out the TOA, and the 4 is the adjacent so we take out the SOH, we have CAH now, so we use cos. Now equation time....
since x is the bottom we switch
, which equals 8. AB=8.
Now to find the perimeter. We still use the 4 to find the hypotenuse so we can find the outside side. For this one they tell us to use 45, so now lets see what method we use. SOH-CAH-TOA. We need the hypotenuse and they give us the adjacent, so we use cos again. Now setting up the equation...
x is at the bottom again to we switch.
which equals to 5.657 or you can round it. Now we add everything.
20+12+5.657+5.657= 45.314 or you can round it to 45.
In geometry, it would be always helpful to draw a diagram to illustrate the given problem.
This will also help to identify solutions, or discover missing information.
A figure is drawn for right triangle ABC, right-angled at B.
The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.
We will be using the first two of the three metric relations of right triangles.
(1) BC^2=CD*CA (similarly, AB^2=AD*AC)
(2) BD^2=CD*DA
(3) CB*BA = BD*AC
Part (A)
From relation (2), we know that
BD^2=CD*DA
substitute values
8^2=x*(4x) => 4x^2=64, x^2=16, x=4
so CD=4, DA=4*4=16 (and AC=16+4=20)
Part (B)
Using relation (1)
AB^2=AD*AC
again, substitute values
AB^2=16*20=320=8^2*5
=>
AB
=sqrt(8^2*5)
=8sqrt(5)
=17.89 (approximately)