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Elden [556K]
3 years ago
6

On Mars, the acceleration due to gravity is 3.77 m / s 2 . 3.77 m/s2. How far would a 15 g 15 g rock fall from rest in 2.5 s 2.5

s if the only force acting on it was the gravitational force due to Mars?
Physics
2 answers:
Zinaida [17]3 years ago
7 0

Answer:

s = 11.78 m

Explanation:

given,

acceleration due to gravity, g = 3.77 m/s²

mass of the rock = 15 g

time = 2.5 s

distance traveled = ?

using equation of motion

s = ut +\dfrac{1}{2}at^2

initial speed = 0 m/s

s = \dfrac{1}{2}at^2

s = \dfrac{1}{2}\times 3.77 \times 2.5^2

s = 11.78 m

distance traveled by the rock is equal to 11.78 m.

chubhunter [2.5K]3 years ago
5 0

Answer:

Explanation:

acceleration, a = 3.77 m/s²

mass, m = 15 g = 0.015 kg

time, t = 2.5 s

Gravitational force, F = mass x acceleration

F = 0.015 x 3.77

F = 0.05655 N

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At t = (70 / 3) \; {\rm s} (approximately 23.3 \; {\rm s}.)

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\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}.

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Hence, the car would catch up with the truck at t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}.

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