1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
3 years ago
5

Suppose you take a trip to a distant universe and find that the periodic table there is derived from an arrangement of quantum n

umbers different from the one on Earth. The rules in that universe are: principal quantum number ????=1,2,... (as on Earth); angular momentum quantum number ℓ=0,1,2,...,????−1 (as on Earth); magnetic quantum number ????ℓ=0,1,2,...,ℓ (only positive integers up to and including ℓ are allowed); spin quantum number ????s=−1,0,+1 (that is, three allowed values of spin). Assuming that the Pauli exclusion principle remains valid in the distant universe, what is the maximum number of electrons that can populate a given orbital there? maximum number electrons per orbital: Write the electronic configuration of the element with atomic number 8 in the periodic table. Superscript numbers where appropriate but omit parentheses. electronic configuration:
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

  • <em>Maximun number of electrons per orbital:</em> <u>3</u>
  • <em>Electron configuration of the element with atomic number 8</em>:

           <u>1s³ 2s³ 2p²</u>

Explanation:

<u>1) Pauli's exclusion principle.</u>

Pauli's exclusion principle states that none two electrons of an atom may have the same set of quantum numbers.

Since the real rule (in our normal universe) is that the spin quantum number can only have two values (s = +1/2 or -1/2), that implies that only two electrons can populate a given orbital here.

<u>2) Rules in the distant universe.</u>

  • The rules for the principal quantum number (n), and the angular momentum quantum number (ℓ), are the same of the Earth.

  • The rule for the magnetic quantum number (mℓ) is different than in the Earth:

        - In the Earth: mℓ = from - ℓ to + ℓ

        - In the distant universe: mℓ = from 0 to ℓ

The implication of this is that there will be only two p orbitals in the distant universe, correponding to ℓ = 0 and ℓ = 1,  instead of three p orbitals as in the Earth.

  • The rule for the spin (ms) number is different than in Earth:

        - In Earth: s = +1/2 or -1/2 (two possibilities)

        - In the distant universe: ms = -1, 0, - 1

Then in each s or p orbital there will be 3 electrons.

<u>3) Electron configuration in the distant universe</u>

Hence, for the element with atomic number 8, which means that the number of electrons is 8, the configuration is:

  • 1s³ (because 3 electrons can populate this orbital)
  • 2s³ (because 3 electrons can populate the second s orbital
  • 2p² (because the 2 remaining electrons can be placed in the orbitals p: remember that in this distant universe there are two p orbitals, so you can accomodate until 6 electrons in them, 2 × 3 = 6.

<u>Conclusion:</u>

  • Maximun number of electrons per orbital: 3
  • Electron configuration of the element with atomic number 8:

             1s³ 2s³ 2p²

You might be interested in
I’m confused on this one
eduard

The question is asking you to find the measure of YZ's arc.

The arc of a circle is found by finding the central angle. In this case, that's angle YCZ. Remember that a circle's total degrees is 360. Since the angle that you are trying to find is 16% of the circle, you need to find 16% of 360.

360*0.16 = 57.6

The measure of arc YZ is 57.6 degrees.

6 0
2 years ago
State the restrictions, if any.<br> F(x)= x/x2-81
Crazy boy [7]

Answer:

f=1/x^2-81

Step-by-step explanation:

Step 1: Multiply both sides by x^2-81.

fx3−81fx=x

Step 2: Factor out variable f.

f(x3−81x)=x

Step 3: Divide both sides by x^3-81x.

f(x3−81x)

x3−81x =x x3−81x f= 1 x2−81

3 0
3 years ago
Certain items are purchased jointly. If each person pays 8coins, the surplus is 3coins, and if each person gives 7coins, the def
kicyunya [14]

Answer:

  • 7 people
  • 53 coins

Step-by-step explanation:

The problem statement tells us ...

  8x = y +3

  7x = y -4

Subtracting the second equation from the first gives ...

  x = 7

Then ...

  y = 7x +4 = 7·7 +4 = 53

There are 7 people, and 53 coins are required for purchase.

4 0
3 years ago
Read 2 more answers
PART A: A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the tr
Greeley [361]

Complete Question:

Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.  

(b) Determine the scale factor from the first map to the second map.

(c)  A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?  

(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:

Answer:

(a) Length = 4cm

(b) Scale factor = 0.5

(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

Length =4cm <em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>

(b) The scale factor

The scale factor (k) is calculated as:

k = \frac{New\ Length}{Old\ Length}

k = \frac{4cm}{8cm}\\

k = 0.5

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

k = \frac{New\ Length}{Old\ Length}

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

New\ Length = k * Old\ Length

When Length = 3cm

New\ Length = 0.5 * 3cm = 1.5cm

When Length = 4cm

New\ Length = 0.5 * 4cm = 2cm

When Length = 5cm

New\ Length = 0.5 * 5cm = 2.5cm

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

7 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is 25 more than 50 as an expression
    12·2 answers
  • Charlie has $12 saved already. He earns another $10 for each lawn he mows. How many lawns must he now before he has $100 saved?
    9·1 answer
  • Can anyone show me how To do this! Please
    8·1 answer
  • What is 3/4 times 6 to the power of 3
    6·2 answers
  • 1.... (0²)²<br><br>2.... (2-3)²
    10·1 answer
  • The length of a rectangular park is 20 feet longer than the width of the park. If the lenght of the park is 36 feet, what is the
    8·1 answer
  • PLEASE HELP!!!
    12·1 answer
  • A 4-centimeter rod is attached at one end A to a point on a wheel of radius 2 cm. The other end B is free to move back and forth
    8·1 answer
  • Which of the following states the law of universal gravitation?
    5·2 answers
  • What relationship do you notice between the squares of<br> the right triangle?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!