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julia-pushkina [17]
3 years ago
12

What is the percentage composition of each element in ammonia, NH3?

Chemistry
1 answer:
laiz [17]3 years ago
5 0
Pneumonia is caused when an H3 is positive to any form so therefore the answer would be the element of a pneumonia will be a positive 6392
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A section of the crust moves under another section of crust without changing the land above. From the surface thebprocess would
joja [24]
Tectonic shift/movement
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3 years ago
How are chloroplast and mitochondrion organelles similar
RUDIKE [14]

Answer: their both in the cell

4 0
3 years ago
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write the spontaneous net cell reaction. include physical states. net cell reaction: 2al(s) 2br {2}(l)
ElenaW [278]

The net cell reaction is: 2Al(s) + 2Br2(l) → 4Br(s) + 2Al2O3(s)

What is a net cell reaction?

A net cell reaction is the overall chemical reaction that occurs during a redox reaction in a cell. It is the sum of all of the individual chemical reactions that take place in the cell and is usually written as an equation with the reactants on the left-hand side and the products on the right-hand side.

What is a chemical reaction?

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8 0
1 year ago
The largest ship in Christopher Columbus' "fleet" was the Santa Maria, which displaced about 100 tons (1 ton = 2,000 pounds) of
Neporo4naja [7]

Answer:

V=97.7m^3

Explanation:

Hello,

In this case, considering that the density is defined in terms of mass and volume as follows:

\rho =\frac{m}{V}

Due to the fact that 100 tons of water were displaced, whose value in grams is:

m=100tons*\frac{1000kg}{1ton} *\frac{1000g}{1kg}=1x10^8g

Thus the displaced volume in cubic meters was:

V=\frac{m}{\rho}=\frac{1x10^8g}{1.024g/mL}  =97656250mL\\\\V=97656250mL*\frac{1L}{1000mL}*\frac{1m^3}{1000L}\\  \\V=97.7m^3

Regards.

7 0
4 years ago
The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. Vanadium-50 has an abundance of 0.250% and a mass
fomenos

Answer:

The answer to your question is letter A

Explanation:

                            Abundance              Atomic mass

       V-50             0.25%                         49.947

       V-51            99.750%                       50.944

Formula

Average atomic mass = [V-50-Abundance x V-50-Atomic mass] +

                                       [ V-51-Abundance x V-51-Atomic mass]

Substitution

Average atomic mass = [ 0.0025 x 49.947] + [0.9975 x 50.944]

                                    = 0.125 + 50.817

Result

                                    = 50.942 amu

4 0
3 years ago
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