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Anton [14]
2 years ago
14

A section of the crust moves under another section of crust without changing the land above. From the surface thebprocess would

seem to be
Chemistry
1 answer:
joja [24]2 years ago
8 0
Tectonic shift/movement
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How many moles are in 12 gr of magnesium?
myrzilka [38]

Answer: 0.5 mole Mg

Explanation: solution:

12 g Mg x 1 mole Mg / 24 g Mg

= 0.5 mole Mg

5 0
3 years ago
Which of the following is a property of a metal?
BaLLatris [955]
The correct answer is the 3rd option Ductility is a property of a metal. It is the ability of a material to deform under tensile stress.It is characterized by the ability to be stretched into wire-like form which is an ability of metals.
8 0
3 years ago
2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of
OleMash [197]

Explanation:

here is the answer bae. Feel free to ask for more

6 0
2 years ago
The reaction below shows how silver chloride can be synthesized.
Vesna [10]
AgNO_{3} _{(aq)}  +  NaCl_{(aq)}  ----\ \textgreater \   NaNO_{3} _{(aq)}   +  AgCl _{(aq)}
mole ration of AgCl _{(aq)}  :  AgNO_{3} _{(aq)} =  1 : 1

∴ if moles of  AgNO_{3} _{(aq)} =  15.0 mol
then   "      "     AgCl _{(aq)}  =  15.0 mol

∴  the Option  2 is the answer.

5 0
3 years ago
Read 2 more answers
What is the empirical formula of a compound that contains 75% Ag and 25% Cl by mass
lesya [120]

Answer:

The answer to your question is     AgCl

Explanation:

Data

Silver = Ag = 75%

Chlorine = Cl = 25%

1.- Convert percent numbers to grams

Silver = 75 g

Chlorine = 25 g

2.- Calculate the moles of each element

Mass number Ag = 108 g

Mass number Cl = 35.5 g

                            108 g of Ag ------------------  1 mol

                              75 g of Ag ------------------   x

                                x = (75 x 1) / 108

                                x = 75 / 108

                                x = 0.69 moles

                            35.5 g of Cl ------------------ 1 mol

                             25 g of Cl    -----------------   x

                                    x = (25 x 1) / 35.5

                                    x = 0.70 moles

3.- Divide by the lowest number of moles

Ag = 0.69/0.69 = 1

Cl = 0.70 / 0.69 = 1.02 ≈ 1

4.- Write the empirical formula

                                                 Ag₁ Cl₁  = AgCl

5 0
2 years ago
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