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wolverine [178]
3 years ago
8

Atom A consists of 10 protons, 12 neutrons, and 10 electrons.

Physics
1 answer:
koban [17]3 years ago
6 0

Answer: They are not isotopes of each other.

Explanation: An isotope is when they have the same number of protons but different number of neutrons. Atom A and Atom B have different amount of protons.

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What happens when you get a concussion?
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Explain how do you determine the intensity of earthquake​
Ivanshal [37]

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The Richter scale measures the largest wiggle (amplitude) on the recording, but other magnitude scales measure different parts of the earthquake. The USGS currently reports earthquake magnitudes using the Moment Magnitude scale, though many other magnitudes are calculated for research and comparison purposes.

6 0
3 years ago
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A wheel rotates about a fixed axis with a constant angular acceleration of 3.3 rad/s2. The diameter of the wheel is 21 cm. What
AleksandrR [38]

Answer:

The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s

Explanation:

We are given that

Angular acceleration, \alpha=3.3 rad/s^2

Diameter of the wheel, d=21 cm

Radius of wheel, r=\frac{d}{2}=\frac{21}{2} cm

Radius of wheel, r=\frac{21\times 10^{-2}}{2} m

1m=100 cm

Magnitude of total linear acceleration, a=1.7 m/s^2

We have to find the linear speed  of a  at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.

Tangential acceleration,a_t=\alpha r

a_t=3.3\times \frac{21\times 10^{-2}}{2}

a_t=34.65\times 10^{-2}m/s^2

Radial acceleration,a_r=\frac{v^2}{r}

We know that

a=\sqrt{a^2_t+a^2_r}

Using the formula

1.7=\sqrt{(34.65\times 10^{-2})^2+(\frac{v^2}{r})^2}

Squaring on both sides

we get

2.89=1200.6225\times 10^{-4}+\frac{v^4}{r^2}

\frac{v^4}{r^2}=2.89-1200.6225\times 10^{-4}

v^4=r^2\times 2.7699

v^4=(10.5\times 10^{-2})^2\times 2.7699

v=((10.5\times 10^{-2})^2\times 2.7699)^{\frac{1}{4}}

v=0.418 m/s

Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s

6 0
3 years ago
A very flexible helium-filled balloon is released from the ground into the air at 20. ∘C. The initial volume of the balloon is 5
koban [17]

Answer:

V = 38.0 L

Explanation:

As we know that number of moles will remains conserved inside the balloon

so we will have

moles = \frac{PV}{RT}

here we have

\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}

now we have

P_1 = 760 mm Hg

P_2 = 76 mm Hg

V_1 = 5.00 L

T_1 = 20^o C = 293 K

T_2 = -50^o C = 223 K

\frac{(760mm Hg)(5L)}{R(293)} = \frac{(76mm Hg)(V)}{R(223)}

V = 38.0 L

5 0
3 years ago
Read 2 more answers
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