Answer:
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Explanation:
Answer:
118750 ml
Explanation:
The chemical equation for complete combustion of hexane is given as;
2C6H14 + 19O2 → 12CO2 + 14H2O
From the equation of the reaction;
2 mol of C6H14 reacts with 19 mol of O2
2 ml of C6H14 reacts with 19 ml of O2
2500 mL of C6H14 would react with x ml of O2
2 = 19
2500 = x
x = 2500 * 19 / 2 = 23750 ml
Since oxygen is 20% of air;
23750 = 20 / 100 * (Volume of air)
Volume of air = 23750 * 100 / 20 = 118750 ml
We know that to relate solutions of with the factors of molarity and volume, we can use the equation:

**
NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.
So now we can assign values to these variables. Let us say that the 18 M

is the left side of the equation. Then we have:

We can then solve for

:

and

or

We now know that the total amount of volume of the 4.35 M solution will be
210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.
Assume an original volume of blood of one deciliter (100 ml). if 5 ml of oxygen diffuses into the blood, 100 ml will be its final volume.
A tissue is made up of white blood cells, platelets, red blood cells, and other elements suspended in a liquid. Blood transports waste away and delivers nutrients and oxygen to the tissues. The entire amount of fluid moving through the heart's arteries, capillaries, veins, venules, and chambers is referred to as blood volume. Red blood cells (erythrocytes), white blood cells (leukocytes), platelets, and plasma are the elements that give blood volume.
The amount of water and sodium ingested, expelled by the kidneys into the urine, and lost through the digestive system, lungs, and skin determines blood volume. The amounts of salt and water that are consumed and excreted vary greatly.
To know more about blood volume refer to: brainly.com/question/7313563
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Answer:
0.158 moles KMnO4
Explanation:
According to the Periodic Table,
K = 39.10 g/mol
Mn = 54.94 g/mol
O = 16.00 g/mol
KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol
25.0 grams KMnO4 1 mole
----------------------------- x -------------------------- = 0.158 moles KMnO4
158.04 grams