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2 years ago

If element x forms the oxides xo and x2o3 the oxidation numbers of element x are

Chemistry

1 answer:

Deffense [45]2 years ago

3 0

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

$XO$

And:

$X_2O_3$

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

$X^{+2}O^{-2}$

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

$X_2^{+3}O_3^{-2}$

Thus, answer is b)+2 and +3

Best regards.

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2 years ago

What is the molecular formula of the following compound: NH_CI, molar mass = 51.5 g/mol?

Helen [10]

Answer:

Explanation:

Explanation:

As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.

In your case, you know that the empirical formula is

NH Cl

, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be

1:2:1.

What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.

Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.

molar mass empirical formula×n=molar mass compound

To get the molar mass of the empirical formula, use the molar masses of its constituent atoms

14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈

51.5 g/mol

This means that you have

51.5g/mol×n=51.5g/mol

As you can see, you have

n=1.

This means that the empirical formula and the molecular formula are equivalent,

NH Cl.

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2 years ago

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