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tigry1 [53]
3 years ago
4

(a) Write the RTL specification for an arithmetic shift right on an eight-bit cell. (b) Write the RTL specification for an arith

metic shift left on an eight-bit cell.

Engineering
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

Please find attached file for complete answer solution and explanation of same question.

Explanation:

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Choose two consumer services careers and research online to determine what kinds of professional organizations exist for these p
Tom [10]

Answer:

Market Researcher

The Marketing Research Association (MRA) is a professional organization for market researchers. It provides information to its members on how to improve marketing research for businesses and individuals. The MRA gives its members important industry news and information through their website. Their code for marketing research standards also protects members from bad actors and improves the public perception of marketing research. The association also has a full time lobbyist representing the market research industry before government officials. The MRA has various membership categories as well. The membership fee differs for each category.  

Credit Analyst

A credit analyst is a person that reviews consumer or business financial profiles in order to give a loan or credit to them. When a business or individual applies for a credit card, loan, trade account, or another type of financial product whereby a company allows them the use of their money, a credit analyst’s job is to ensure that the consumer or business is willing and able to pay it back in the future. Credit analysts use tools such as credit reports, FICO scores, Dun & Bradstreet ratings, financial statement analyses, and personal references to perform their job. A credit analyst should have a bachelor’s degree with a major in business. Finance and economics majors are particularly suited to a credit analyst position. Certifications are not required, but some credit analysts pursue CPA or CFA (Certified Financial Analyst) designations.

Explanation:

5 0
3 years ago
A 75 ohm coaxial transmission line has a length of 2.0 cm and is terminated with a load impedance of 37.5 + j75 Ohm. If the diel
Hatshy [7]

Answer:

The load reflection coefficient, \Gamma =0.62\angle 82.875^{\circ} \Omega

Reflection coefficient at input,  \Gamma = 0.62\angle - 147.518^{\circ} \Omega

SWR = 4.26

Given:

Characteristic impedance of the co-axial cable, Z_{c} = 75 \Omega

Length of the cable, L = 2.0 cm = 0.02 m

Z_{Load} = 37.5 + j75 \Omega

Dielectric constant, K = 2.56

frequency, f = 3.0 GHz = 3.0 \times 10^{9} Hz

Explanation:

In order to calculate the reflection coefficient at load, we first calculate these:

The line input impedance Z_{i} is given by:

Z_{i} = Z_{c}\frac{Z_{Load} + jZ_{c} tan(\beta L)}{Z_{c} + jZ_{Load} tan (\beat L)}                     (1)

Now, we calculate the value of \beta:

\beta = \frac{2\pi}{\lambda'} = \farc{2\pi f\sqrt{K}}{c}

(since, \lambda' = \farc{c}{f\sqrt{K}})

\beta = \farc{2\pi f\sqrt{2.56}}{3\times 10^{8}} = 100.53

Now, Substituting the value in eqn (1):

Z_{i} = 75\frac{37.5 + j75 + j75 tan(100.53\times 0.02)}{75 + j(37.5 + j75) tan ( 100.53\times 0.02)} = 18.99 - j20.55 \Omega = 27.98\angle - 47.257^{\circ} \Omega    

Now, the load reflection coefficient is given by:

\Gamma = \frac{Z_{Load} - Z_{c}}{Z_{c} + Z_{Load}}}

Thus

\Gamma = \frac{37.5 + j75 - 75}{75 + 37.5 + j75}} = 0.077 + j0.615 = 0.62\angle 82.875^{\circ} \Omega

Similarly,

Reflection coefficient at input:

\Gamma' = \frac{Z_{i} - Z_{c}}{Z_{c} + Z_{i}}}

\Gamma' = \frac{18.99 - j20.55 - 75}{75 + 18.99 - j20.55}} = - 0.523 - j0.334 = 0.62\angle - 147.518^{\circ} \Omega

Now, the SWR is given by:

SWR, Standing Wave Ratio = \frac{1 +|\Gamma|}{1 - |\Gamma|}

SWR = \frac{1 +|0.62|}{1 - |0.62|} = 4.26

8 0
3 years ago
52 points+Brainliest for correct answer
pentagon [3]
Divide by 6 and divide the caw of squaw squaw
4 0
2 years ago
Quadrature encoders operate with two photodetectors offset by _______ degrees. (a) 45 (b) 90 (c) 180 (d) 270
Lemur [1.5K]

Answer:

i think it should be 90 degree

5 0
3 years ago
A European car manufacturer reports that the fuel efficiency of the new MicroCar is 48.5 km/L highway and 42.0 km/L city. What a
statuscvo [17]

Answer:

Fuel efficiency for highway = 114.08 miles/gallon

Fuel efficiency for city = 98.79 miles/gallon

Explanation:

1 gallon = 3.7854 litres

1 mile = 1.6093 km

Let's first convert the efficiency to km/gallon:

48.5 km/litre = (48.5 * 3.7854) km/gallon

48.5 km/litre =  183.5919 km/gallon (highway)

42.0 km/litre = (42.0 * 3.7854) km/gallon

42.0 km/litre = 158.9868 km/gallon (city)

Next, we convert these to miles/gallon:

183.5919 km/gallon = (183.5919 / 1.6093) miles/gallon

183.5919 km/gallon = 114.08 miles/gallon (highway)

158.9868 km/gallon = (158.9868 /1.6093) miles/gallon

158.9868 km/gallon = 98.79 miles/gallon (city)

3 0
3 years ago
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