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scZoUnD [109]
3 years ago
7

Which best describes the similarities and differences between the Engineering and Technology pathway and the Science and Math pa

thway?
a) Both pathways require workers to use teamwork, leadership, and teaching skills while the Engineering and Technology pathway requires clerical skills.

b) Both pathways require workers to have observational skills while the Engineering and Technology pathway requires CAD knowledge.

c) Both pathways require workers to be creative, while the Science and Math pathway requires specialized knowledge in subject areas like physics or chemistry.

d) Both pathways require workers to have patience and persistence while the Science and Math pathway requires physical stamina, dexterity, and use of technical equipment.
Engineering
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

Both pathways require workers to be creative, while the Science and Math pathway requires specialized knowledge in subject areas like physics or chemistry.

You might be interested in
Consider a system whose temperature is 18°C. Express this temperature in R, K, and °F.
zvonat [6]

Answer:

In Rankine 524.07°R

In kelvin 291 K

In Fahrenheit 64.4°F  

Explanation:

We have given temperature 18°C

We have to convert this into Rankine R

From Celsius to Rankine we know that  T(R)=(T_{C}+273.15)\frac{9}{5}

We have to convert 18°C

So T(R)=(18+273.15)\frac{9}{5}=524.07^{\circ}R

Conversion from Celsius to kelvin

T(K)=(T_{C}+273)

We have to convert 18°C

T(K)=(18+273)=291K

Conversion of Celsius to Fahrenheit

T(F)=T_{C}\times \frac{9}{5}+32=64.4^{\circ}F

7 0
3 years ago
an object of mass 2kg is released from a top of inclined plane 30° and height 6m. The coefficient of kinetic friction of the sur
mel-nik [20]

Explanation:

1) Work done = force x distance x cos(θ)

= 0.15 x 6 x cos(30)

= 0.779

2) Ek = ½mv²

v = acceleration due to gravity so 9.81

Ek = ½(2)(9.81)²

Ek = 96.2361

3) v = (√(2em)) / m

= (√(2(96.2361)(2)) / 2

= 9.81 so especially with no time given, I can only assume the acceleration due to gravity but take it with a pinch of salt.

5 0
2 years ago
Question 3. Assign boston_under_10 and manila_under_10 to the percentage of rides that are less than 10 minutes in their respect
Sever21 [200]

Answer:

Enter the following code  to get the required conditions for the answer.

boston_under_5_height = 1.2

manila_under_5_height = 0.6

boston_5_to_under_10_height = 3.2

manila_5_to_under_10_height = 1.4

boston_under_10 = boston_under_10 = 5*boston_under_5_height + 5*boston_5_to _under_10_height

manila_under_10 = manila_under_10 = 5*manila_under_5_height + 5*manila_5_to _under_10_height

Explanation:

Kindly note that question in complete as it belong to the topic of table manipulation and visualization topic. The question asks about the company called Uber and their data extraction from the website called movements.uber.com where data was extracted for 200,000 weekdays in the respective cities of Manila, Philippines and Boston, Massachusetts. Images attached contains the histograms generated for the rides in manila and boston.

3 0
4 years ago
Question
pochemuha

Answer:

udhddhdiejebdidjebdhdidh

3 0
3 years ago
Liquid flows at steady state at a rate of 2 lb/s through a pump, which operates to raise the elevation of the liquid 100 ft from
Greeley [361]

Answer:

D) 1.04 Btu/s from the liquid to the surroundings.

Explanation:

Given that:

flow rate (m) = 2 lb/s

liquid specific enthalpy at the inlet (h_{1}=40.09 Btu/lb)

liquid specific enthalpy at the exit (h_{2}=40.94 Btu/lb)

initial elevation (z_1=0ft)

final elevation (z_2=100ft)

acceleration due to gravity (g) = 32.174 ft/s²

W_{cv} = 3 Btu/s

The energy balance equation is given as:

Q_{cv}-W{cv}+m[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0

Since  kinetic energy effects are negligible, the equation becomes:

Q_{cv}-W{cv}+m[(h_1-h_2)+g(z_1-z_2)]=0

Substituting values:

Q_{cv}-(-3)+2[(40.09-40.94)+\frac{32.174(0-100)}{778*32.174} ]=0\\Q_{cv}+3+2[-0.85-0.1285 ]=0\\Q_{cv}+3+2(-0.9785)=0\\Q_{cv}+3-1.957=0\\Q_{cv}+1.04=0\\Q_{cv}=-1.04\\

The heat transfer rate is 1.04 Btu/s from the liquid to the surroundings.

8 0
3 years ago
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