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2 years ago

12

Need help on this question I’d really appreciate it thanks!

1 answer:

ELEN [110]2 years ago

6 0

Answer:radiation

Explanation:

radiation is the only one that makes sense

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A long wire carries a current density proportional to the distance from its center, J=(Jo/ro)•r, where Jo and ro are constants a

IgorC [24]

Answer:

$B = \mu_0(\frac{1}{3} \frac{J_0}{r_0} r^2)$

Explanation:

As the current density is given as

$J = \frac{J_0}{r_0}r$

now we have current inside wire given as

$i = \int J(2\pi r)dr$

$i = \int \frac{J_0}{r_0} r(2\pi r)dr$

$i = 2\pi \frac{J_0}{r_0} \int r^2 dr$

$i = \frac{2}{3} \pi \frac{J_0}{r_0} r^3$

Now by Ampere's law we will have

$\int B. dl = \mu_0 i$

$B. (2\pi r) = \mu_0(\frac{2}{3} \pi \frac{J_0}{r_0} r^3)$

$B = \mu_0(\frac{1}{3} \frac{J_0}{r_0} r^2)$

4 0

2 years ago

Suzanne makes a tower out of six identical plastic box. Then she uses a pan balance to measure the mass of the tower. She finds

EleoNora [17]

Take the 72 g and divid it by 6 which would equal 12 g each

5 0

3 years ago

Read 2 more answers

The tape in a videotape cassette has a total

Softa [21]

Answer:

1.37 rad/s

Explanation:

Given:

Total length of the tape is, $d= 297$ m

Total time of run is, $t = 2.1$ hours

We know, 1 hour = 3600 s

So, 2.1 hours = 2.1 × 3600 = 7560 s

So, total time of run is, $t= 7560$ s

Inner radius is, $r = 10\ mm = 0.01\ m
$

Outer radius is, $R = 47\ mm = 0.047\ m
$

Now, linear speed of the tape is, $v =\frac{d}{t}=\frac{297}{7560}=0.039\ m/s
$

Let the same angular speed be $\omega$ .

Now, average radius of the reel is given as the sum of the two radii divided by 2.

So, average radius is, $R_{avg}=\frac{R+r}{2}=\frac{0.047+0.01}{2}=\frac{0.057}{2}=0.0285\ m
$

Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,

$\omega=\dfrac{v}{R_{avg}}\\\\\\\omega=\dfrac{0.039}{0.0285}\\\\\\\omega=1.37\ rad/s
$

Therefore, the common angular speed of the reels is 1.37 rad/s.

5 0

3 years ago

Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to t

yarga [219]

Answer

The rate at which the magnetic field is changing is $[\frac{dB}{dt} ] = 0.000467 T/s$

Explanation

From the question we are told that

The electric field strength is $E = 3.5mV/m = 3.5 *10^{-3} \ V/m$

The radius is $r = 1.5 \ m$

The rate of change of the magnetic field is mathematically represented as

$\frac{d \phi }{dt} = \int\limits^{} {E \cdot dl}$

Where $dl$ is change of a unit length

$\frac{d \phi}{dt} = A * \frac{dB}{dt}$

Where A is the area which is mathematically represented as

$A = \pi r^2$

So

$E \int\limits^{} { dl} = ( \pi r^2) (\frac{dB}{dt} )$

$E L = ( \pi r^2) (\frac{dB}{dt} )$

where L is the circumference of the circle which is mathematically represented as

$L = 2 \pi r$

So

$E (2 \pi r ) = (\pi r^2 ) [\frac{dB}{dt} ]$

$E = \frac{r}{2} [\frac{dB}{dt} ]$

$[\frac{dB}{dt} ] = \frac{E}{ \frac{r}{2} }$

substituting values

$[\frac{dB}{dt} ] = \frac{3.5 *10^{-3}}{ \frac{15}{2} }$

$[\frac{dB}{dt} ] = 0.000467 T/s$

8 0

3 years ago

a ball is dropped and falls with an acceleration of 9.8m/s^2 downward. it hits the ground with a velocity of 49m/s downward. how

yaroslaw [1]

The answer below...........

8 0

3 years ago