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3 years ago

According to Newton's first law of motion, what will an object in motion do when

Physics

2 answers:

ivann1987 [24]3 years ago

6 0

It could speed up, change direction, come to a complete stop, or slow down without stopping.

The one thing the object could NOT do is keep moving with the same velocity. Its velocity must change.

kolezko [41]3 years ago

4 0

Answer:

The Answers B, move at the same velocity

Explanation:

bruh

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A 75-kilogram hockey player is skating across the ice at a speed of 6.0 meters per second. What is the magnitude of the average

saveliy_v [14]

Answer:

(3) 690 N

Explanation:

Force: This is the product of mass and acceleration of a body. The S.I unit of force is Newton(N).

The formula for force is given as,

F = ma..................... Equation 1

Where F = force, m = mass, a = acceleration.

Also,

a = (v-u)/t................... Equation 2

Where v = Final velocity, u = initial velocity, t = time.

Given: u = 6.0 m/s, v = 0 m/s (bring to stop), t = 0.65 s.

Substitute into equation 2

a = (0-6)/0.65

a = -6/0.65

a = -9.23 m/s²

Also given: m = 75 kg

Substitute again into equation 1

F = 75(-9.23)

F = -692.25 N

The negative sign tells that the force oppose the motion of the player

F ≈ 690 N

Hence the right option is (3) 690 N

3 0

3 years ago

How many water (in kg) can raise its temperature from 23°C to 100°C by adding 21500 Joules of energy?

igomit [66]

Answer: Approximately 8.0g of water

Explanation:

4 0

3 years ago

How is newtons third law of motion demonstrated on a roller coaster?

butalik [34]

<span>Newton's Third Law of Action-Reaction is that for each and every action that happens, there is an equal and opposite reaction to it. In the scenario of a roller coaster, this is when you push down on the seat of the roller coaster as it flies along and the seat pushes back against you.</span>

8 0

3 years ago

Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air

frosja888 [35]

The frequency of the wave has not changed.

In fact, the frequency of a wave is given by:

$f=\frac{v}{\lambda}$