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ad-work [718]
3 years ago
7

To qualify for Gold status at Awesome Airlines, one must fly less than 2280022800 but at least 96009600 miles each year. If Greg

takes a 600600-mile round-trip flight when visiting his parents, how many times does Greg need to visit his parents each year to attain Gold status? Express your answer in interval notation.
Physics
1 answer:
sattari [20]3 years ago
8 0

Answer: n; 160 =< n < 3796

Explanation:

Number of miles needed to claim Gold d has the range

{d; 2280022800 > d >= 96009600}

Greg goes 600600miles in a year

dGreg = 600600mi

Lower limit for a Gold status is 96009600

Thus, we find the lower limit of number of trips

n = d/dGreg

(d here is the lower distance per year to be covered in order to attain Gold)

n(lower) = 96009600/600600

= 159.8561 ~ 160 trips

n(higher) = 2280022800/600600

= 3796.24 ~ 3796 trips

In interval notation

n; 160 =< n < 3796

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The maximum pressure variations the human ear can withstand are about how much above and below atmospheric pressure?
Crank

The maximum pressure variations the human ear can withstand  above and below atmospheric pressure is around 30 pa. the normal atmospheric pressure is around 101325 pa. hence the variation in the maximum pressure for human ear is very small as compared to the atmospheric pressure. if the ear is exposed to a pressure greater than this , it can cause permanent damage to the ear.

4 0
3 years ago
Describe how a planet, solar system, galaxy, and the universe are related in terms of size.
Alexus [3.1K]

- The Solar System contains the sun and objects that orbit it, including the eight planets, comets, and asteroids, and the Galaxy contains about 100 billion stars, of which the sun is one, as well as large clouds of gas and dust. - The universe contains all physical matter and energy

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7 0
2 years ago
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.32 with the floor. If t
coldgirl [10]

Answer:

The shortest braking distance is 35.8 m

Explanation:

To solve this problem we must use Newton's second law applied to the boxes, on the vertical axis we have the norm up and the weight vertically down

On the horizontal axis we fear the force of friction (fr) that opposes the movement and acceleration of the train, write the equation for each axis

    Y axis

     N- W = 0

     N = W = mg

  X axis

     -Fr = m a

     -μ N = m a

     -μ mg = ma

     a = μ g

     a  = - 0.32 9.8

     a =  - 3.14 m/s²

We calculate the distance using the kinematics equations

    Vf² = Vo² + 2 a x

     x = (Vf² - Vo²) / 2 a

When the train stops the speed is zero (Vf = 0)

 Vo = 54 km/h (1000m/1km) (1 h/3600s)= 15 m/s

     x = ( 0 - 15²) / 2 (-3.14)

     x=  35.8 m

The shortest braking distance is  35.8 m

7 0
2 years ago
(this is a question from my leap practice)
ki77a [65]
The answer is C. in sort of a way. You can't technically see black matter. However, it is holding the galaxies together.
4 0
3 years ago
A circular loop of wire with radius r=0.0250 m and resistance r=0.390 ohms is in a region of spatially uniform magnetic field. t
slavikrds [6]

Answer:

0.0133 A

Explanation:

The time at which B=1.33 T is given by  

1.33 = 0.38*t^3  

t = (1.33/0.38)^(1/3) = 1.52 s  

Using Faraday's Law, we have  

emf = - dΦ/dt = - A dB/dt = - A d/dt ( 0.380 t^3 )  

Area A = pi * r² = 3.141 *(0.025 *0.025) = 0.00196 m²

emf = - A*(3*0.38)*t^2  

thus, the emf at t=1.52 s is  

emf = - 0.00196*(3*0.38)*(1.52)^2 = -0.0052 V  

if the resistance is 0.390 ohms, then the current is given by  

I = V/R = 0.0052/0.390 = 0.0133 A

3 0
2 years ago
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