Answer:
B
Explanation:
Given:-
- The charge of the test particle q = 3.0 * 10^-9 C
- The force exerted by the metal sphere F = 6.0 * 10^-5 N
Find:-
The magnitude and direction of the electric field
strength at this location?
Solution:-
- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:
F = E*q
- Using the data given we can determine E:
E = F / q
E = (6.0 * 10^-5) / (3.0 * 10^-9)
E = 20,000 N/C
- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.
Answer:
a. 12,600 N
b. 1290 kg
Explanation:
a. Impulse = change in momentum
F Δt = m Δv
F (0.192 s) = (59 kg) (0 m/s − 41 m/s)
F = -12,600 N
b. F = mg
12,600 N = m (9.8 m/s²)
m = 1290 kg (or 2,830 lbs)
Your answer is C. Dark Matter.
It is a reflecting telescope and a compound microscope. I know this for sure
Explanation:
F = Gm1m2/r^2
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