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S_A_V [24]
2 years ago
11

HELP PLEASEEEEE KAJAMAAKAOAAJAKAKJSMALASJSSJKSSKSJSMKSLWWMSMSKLSSLSKSMMSMSKSKSOSKSSMMSMSKSKSSKMSMSMSMSKSMMSNSSMMSMSMSMSMSKSKSLSL

SSMSMMSKSSLPWWOWKWKWKWLWOQISMSMSMSMWKWKWKWKWKWKWKWKKWLW

Chemistry
1 answer:
wariber [46]2 years ago
8 0

Answer:

the cirle of life

Explanation:

i am smart

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Phosphoric acid is a triprotic acid with the follow Ka values: Ka1 = 7.2x10−3, Ka2 = 6.3x10−8, Ka3 = 4.2x10−13 Based on this inf
klasskru [66]

Answer:

Explanation:

Step 1

Phosphoric Acid is a triprotic acid where H3PO4 dissociates to H2PO4- which then further dissociates HPO42- and it then forms PO43-. Equation for acid dissociation constant for the dissociation of H3PO4 and HPO42- can be written as above.

Step 2

Concentration of H2PO4- produces during the dissociation of H3PO4 can be determined by constructing an ICE table.

Step 3

Concentration of HPO42- produces during the dissociation of H2PO4- can be determined

3 0
3 years ago
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Does SiO2 also equal Si2O4?<br> (silicon atom 1 oxygen atom 2 = silicon atom 2 oxygen atom 4?)
Norma-Jean [14]

Answer:

7

Explanation:

that is the anwer of the question

8 0
2 years ago
What is the valence electron configuration for the oxygen atom
Lana71 [14]
Oxygen has six valence (outer-shell) electrons so therefore gains two more electrons to form the O-2 ion Its electron configuration is: 1s2 2s2 2p6 or Ne

If this helped mark Brainliest!
8 0
3 years ago
What type of change forms a new<br> substance?
marusya05 [52]

Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products.

6 0
3 years ago
45 The mass of an unidentified metal sphere is 133 grams. Students determine the
Lisa [10]

Answer:

D Cobalt

Explanation:

The volume of the sphere is  40 -25 = 15 cm^3

Density = mass/volume = 133 gm / 15 cm^3 = 8.87 gm/cm^3

  which corresponds to Cobalt from the chart

7 0
2 years ago
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