Answer:
In the absence of urease this will take 950 * 10^6 years to completely hydrolyze
Explanation:
The enzyme urease enhances the rate of urea hydrolysis at pH 8.0 and 20 degrees by a factor of 10^14 . If a given quantity of urease can completely hydrolyze a given quantity of urea in 5 min at 20 degrees and pH 8.0, how long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease?
Step 1: data given
The enzyme urease enhaces the rate of urea hydrolysis at pH = 8.0 of centigrade by a factor of 10^14
Temperature = 20.0 °C
Step 2: Calculate the time it takes to completely hydrolyze without urease
This means when urease is available it takes 5 minutes to completely hydrolyze
When urease is not available it will take 5 *10^14 minutes
5 * 10^14 min = 5 * 10^14 minutes
Since 1 hour = 60 minutes
1 day = 24 hours = 24 *60 minutes = 1440 minutes
It would take : 5 * 10^14 minutes / 1440 minutes = 347222222222.2 days
Since 1 year = 365 days
This will take: 347222222222.2 / 365.25 = 950642634.4 years
This 950 * 10^6 years
In the absence of urease this will take 950 * 10^6 years
Answer:
ask them. it doesn't really hurt to.
The freezing point is the temperature at which things freeze.
How do the isotopes of a given element differ from one another? Since the isotopes of any given element all contain the same number of protons, they have the same atomic number. However, since the isotopes of a given element contain different numbers of neutrons<span>,different isotopes have different </span>mass<span> numbers</span>