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Burka [1]
3 years ago
7

Freediving is an activity in which a person dives, sometimes to great depth, without the use of scuba gear. The diver must hold

his or her breath for the duration of the dive. The record depth, with no equipment such as diving fins, is 101 m; the official record time is over 11 minutes. Historically, freediving has been used by pearl divers and sponge divers. Some freedivers hyperventilate (breathe rapidly and deeply) before diving. Hyperventilation can change the concentration of CO2 in the blood and may increase the length of time that a person feels like he or she can hold his or her breath. How does hyperventilation affect blood pH?
Chemistry
1 answer:
Luden [163]3 years ago
6 0

Explanation:

Carbon dioxide is eliminated from the body as a gas through exhaled air. When the volumes of air breathed into and out of the lungs increases above what is normal (hyperventilation), more carbon dioxide than normal is eliminated.

When carbon dioxide is dissolved in water forms carbonic acid which is an acid, having less CO2 in the system affects the balance of the normal pH tips towards the blood pH to become alkaline (higher pH), this condition is called respiratory alkalosis.

We can observe the equilibrium in this equation:

CO2 + H2O ← H2CO3 ← H+ + HCO3

<em>Here we observe how losing CO2 during hyperventilation leads to a decrease of H+ and therefore an increase in pH</em>.

I hope you find this information useful and interesting! Good luck!

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What type of change is the following: striking a match chemical, or physical?
chubhunter [2.5K]
Chemical,when you light a match stick, you are starting a chain reaction of the substance chemical formula, making it a chemical change
7 0
3 years ago
The question is in the picture below
Rus_ich [418]

Answer:

\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

\bf{\text{A} \rightarrow 2\text{B}}                  (Δ\text{H}_1)  -----(1)

Since we have 2B, multiply the whole of II. by 2:

\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}       (2Δ\text{H}_2) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is \text{A} \rightarrow 2\text{C} +2\text{D}.

Reversing III. gives us a negative enthalpy change as such:

\bf{2\text{D} \rightarrow \text{E}}                  (-Δ\text{H}_3) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of \text{A} \rightarrow 2\text{C} +\text{E}, which is also the equation of interest.

Adding all three together:

\text{A} \rightarrow 2\text{C}+\text{E}            (\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 })

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

4 0
1 year ago
How many molecules are in 0.79 moles of NH4?
erik [133]

Answer:

14

Explanation:

5 0
2 years ago
Why is BCl3 a non-polar compound?​
Firdavs [7]

Answer:

BCI3 is a non polar compound because there is no neutral in it

4 0
3 years ago
What is the total amount of heat released when 94.0 g water at 80.0 °C cools to form ice at −30.0 °C?
Wewaii [24]

Answer:

The total amount of heat released  is  68.7 kJ

Explanation:

Given that:

mass of water = 94.0 g

moles of water = 94 / 18.02 = 5.216

80⁰C   ------>  0⁰C  -------->    -30⁰C

Q1 = m Cp dT

      = 94 x 4.184 x (0 - 80)

     = -31463.68 J

     = -31.43 kJ

Q2 = 6.01 x 10^3 x 5.216

    = - 31348.16 J

   = -31.35 kJ

Q3 = - 94 x 2.09 x 30

    = - 5893.8 J

   = -5.894 kJ

Total heat = Q1 + Q2 + Q3  = -31.43 kJ  + (-31.35 kJ  ) + (-5.894 kJ )  = -68.7 kJ

Total heat released = -68.7 kJ

Note that the "negative sign" simply indicates heat released, therefore no need to put it in the answer.

6 0
3 years ago
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