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lions [1.4K]
2 years ago
15

Which of the following statements about lunar phases is true? (A) Only one quarter of the first-quarter moon is illuminated by t

he Sun.(B) It is possible to have two full moons during January, but not during February.(C) It is possible to have two full moons during November, but not during December.(D) The time between new moons is two weeks.(E) The full moon sometimes rises around midnight.
Physics
1 answer:
saul85 [17]2 years ago
7 0

Answer:

A) False B) True C) False D) False E) False

Explanation:

A) At any point of time half of the moon is always illuminated by the sun. We are able to see only the part of the moon which is facing us.

B)  Typically a Lunar cycle phases take 29.5 days to complete one cycle i.e. it will take 29.5 days for one event say full moon to reoccur. So except for February all the other month can have two full moons.

C) As explained in the above answer any month except February can have two full moons.

D) The tame taken between new moon is 29.5 days.

E) Full moon always rises at the sunset and sets at the sunrise

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In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find
Gekata [30.6K]

Answer:

a)P(6)=0.25

b)p(x

c)p(x\geq3)=0.9878

d)\sigma=\sqrt{2.4}=1.5492

Explanation:

From the question we are told that:

Population percentage p_\%=\60%

Sample size n=10

Let x =customers ask for water

Let y =customers dose not ask for water with their meal  

Generally the equation for y is mathematically given by

y=1-p_\%\\y=1-0.60\\y=0.40

Generally the equation for pmf p(x) is mathematically given by

P(x)=10C_x (0..6)^x(0.4)^{10-x}

a)

Generally the probability that exactly 6 ask for water is mathematically given by

P(x)6=10C_6 (0..6)^6(0.4)^{10-6}

P(6)=0.25

b)

Generally the probability that  less than 9 ask for water with meal  is mathematically given by

p(xg)

p(x

p(x

p(x

c)

Generally the probability that  at least 3 ask for water with meal  is mathematically given by

p(x\geq3)=1-p(x

p(x\geq3)=1-[p(0)+p(1)+p(2)]

p(x\geq3)=1-[0.00001+0.0015+0.0106]

p(x\geq3)=1-[0.0122]

p(x\geq3)=0.9878

d)

Generally the mean and standard deviation of sample size is mathematically given by

Mean

\=x=np=10(0.6)=6

Standard deviation

v(x)=npq=10(0.6)(0.4)=2.4

\sigma=\sqrt{2.4}=1.5492

4 0
3 years ago
What is the safety rules?
Black_prince [1.1K]

Answer:

Quick question do you mean what are some safety rules

Explanation:

Crosswalk, Stop sign,

5 0
3 years ago
Read 2 more answers
A wall (of thermal conductivity 0.98 W/m · ◦ C) of a building has dimensions of 3.7 m by 15 m. The average inside and outside
disa [49]

Answer:

Answer:

the amount of energy flowing is 1.008x10⁹J

Explanation:

To calculate how much heat flows, the expression is the following:

Where

K=thermal conductivity=0.81W/m°C

A=area=6.2*12=74.4m²

ΔT=30-8=22°C

L=thickness=8cm=0.08m

t=time=16.9h=60840s

Replacing:

Explanation:

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2 years ago
What would we see looking across a flat land of the earth was curved?
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You would see mountains off in the distance as if the earth was actually flat. but it seems flat because its so big
7 0
3 years ago
The aeroplane lands at a speed of 80 m/s
strojnjashka [21]

The mass of the aeroplane is 300,000 kg.

<h3>What is Newton's second law of motion?</h3>

It states that the force F is directly proportional to the acceleration a of the body and its mass.

The law is represented as

F =ma

where acceleration a = velocity change v / time interval t

Given is the aeroplane lands at a speed of 80 m/s. After landing, the aeroplane takes 28 s to decelerate to a speed of 10 m/s. The mean resultant force on the aeroplane as it decelerates is 750 000 N.

The force expression will be

F = mv/t

Substitute the values and we have

750000 = m x  (80 -10)/ 28

750,000 = m x 2.5

m = 300,000 kg

Thus, the mass of the aeroplane is 300,000 kg.

Learn more about Newton's second law of motion.

brainly.com/question/13447525

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8 0
2 years ago
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