Answer: The horizontal location of the plane will BE OVER THE BOMB
Explanation:
As soon as the bomb was dropped, the bomb will fall under gravity (free fall) and the location of the plane continues to increase horizontally till the bomb reaches the ground which is a falling distance to be travelled by the bomb at 9.8m/s²
Answer:
0.3659
Explanation:
The power (p) is given as:
P = AeσT⁴
where,
A =Area
e = transmittivity
σ = Stefan-boltzmann constant
T = Temperature
since both the bulbs radiate same power
P₁ = P₂
Where, 1 denotes the bulb 1
2 denotes the bulb 2
thus,
A₁e₁σT₁⁴ = A₂e₂σT₂⁴
Now e₁=e₂
⇒A₁T₁⁴ = A₂T₂⁴
or

substituting the values in the above question we get

or
=0.3659
<h3>Answer</h3>
m/s^2 (meter per sec square)
Explanation:
acc = change in velocity/time
= distance/time
----------------
time
= m/s
------
s
=m/s^2
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