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oee [108]
3 years ago
7

Bottlenose dolphins use echolocation pulses with a frequency of about 100 kHz, higher than the frequencies used by most bats. Wh

y might you expect these water-dwelling creatures to use higher echolocation frequencies than bats?
a. Word Bank-b. smallerc. inversed. directe. greater
Physics
1 answer:
Alinara [238K]3 years ago
8 0

Answer:

1. greater

2. direct

3. smaller

4. inverse

Explanation:

The speed of sound in water is greater than in air; hence for the same frequency the sound wavelength in water is <u>greater </u>than in air (for the given frequency the wavelength is in the <u>direct </u>proportion with the speed of sound).

To "see" an object via the echolocation creature needs to use sound with the wavelength <u>smaller </u>than the size of an object viewed.

That means to "see" objects of the same size dolphin and bat need to use ultrasound of the same wavelength, hence dolphin needs to use higher frequency (for the given speed of sound the wavelength is in <u>inverse </u>proportion with the frequency).

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An isolated conducting sphere has a 12 cm radius. One wire carries a current of 1.0000049 A into it while another wire carries a
tatuchka [14]

Answer:

it will take for the sphere to increase in potential by 1500 V, 503.71 s.

Explanation:

The charge on the sphere after t seconds is:

q = (1.0000049 - 1.0000000) t = 0.0000049 t

The voltage on the surface is

V = k * \frac{q}{R} = k 0.0000049 t / R

solve for t

t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * 9e^{9}) = 503.71 s

7 0
4 years ago
Where is energy being applied to the system?
Aleksandr-060686 [28]
Well i cant answer the first question due to absence of diagram
For the second queation, the energy affects the Frequency of wave, the higher the ebrgy the higher the frequency. Since frequency =1/Period,energy can also be said to alter the period. Since wave speed = Frequency *Wavelength, the speed is also increase due to increase in the frequency.
its amplitude increases too by the way.
3 0
4 years ago
Calculate the impulse imparted when a 3,000-kg car hits a wall at 60 . m/s and comes to a stop.
Pani-rosa [81]

Impulse = change in momentum


The answer is 0.

7 0
3 years ago
The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five
leva [86]

Answer:

a

 l = 0.305 \  m

b

  f = 3.0*10^{11} \  Hz

Explanation:

From the question we are told that

  The  wavelength is  \lambda  =  12.2 \  cm  = 0.122 \  m

  The  number of antinodal planes of the electric field considered is n  =  5

The  width is mathematically represented as

       l  =  \frac{ n \lambda}{2}

       l = \frac{5 * 0.122 }{ 2}

      l = 0.305 \  m

Generally the  frequency the errors was made is  mathematically represented as

   f =  \frac{c}{\lamda_k}

Here c is the speed of light with value  c =  3.0*10^{8} \  m/s

     \lambda_k is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as

     \lambda_k  =  \frac{ \lambda *  \frac{0.04}{2} }{n/2}

      \lambda_k  =  \frac{0.122*0.02}{5/2}

So

   f =  \frac{3.0*10^{8}}{0.000976}

    f = 3.0*10^{11} \  Hz

   

       

8 0
3 years ago
a new planet is discovered that has twice the earth’s mass and twice the earth’s radius. on the surface of this new planet, a pe
Irina18 [472]

Answer: 250n

Explanation:

The formula for gravitational force is: F = (gMm)/r^2

There are two factors at play here:

1) The mass of the planet 'M'

2) The radius 'r'

We can ignore the small M and the g, they are constants that do not alter the outcome of this question.

You can see that both M and r are double that of earth. So lets say earth has M=1 and r=1. Then, new planet would have M=2 and r=2. Let's sub these two sets into the equation:

Earth. F =  M/r^2 = 1/1

New planet. F = M/r^2 = 2/4 = 1/2

So you can see that the force on the new planet is half of that felt on Earth.

The question tells us that the force on earth is 500n for this person, so then on the new planet it would be half! So, 250n!

8 0
3 years ago
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