Answer:
7213.7kg/m³
Explanation:
Given parameters:
Volume of the metal chunk = 0.131m³
Mass of the metal chunk = 945kg
Unknown:
Density of the metal chunk = ?
Solution :
To solve this problem, density is the mass per unit volume. It is mathematically expressed as;
Density = 
So;
Density = 
= 7213.7kg/m³
Answer:
A) a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²
Explanation:
Part A) The relation of the test tube is centripetal
a_c = v² / r
the angular and linear variables are related
v = w r
we substitute
a_c = w² r
let's reduce the magnitudes to the SI system
w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s
r = 1 cm (1 m / 100 cm) = 0.10 m
let's calculate
a_c = 418.88² 0.1
a_c = 1.75 10⁴ m / s²
part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor
as part of rest the initial velocity is zero and on the floor the height is zero
v² = v₀² - 2g (y- y₀)
v² = 0 - 2 9.8 (0 + 1)
v =√19.6
v = -4.427 m / s
now let's look for the applied steel to stop the test tube
v_f = v + a t
0 = v + at
a = -v / t
a = 4.427 / 0.001
a = 4.43 10³ m / s²
Answer:
thermal
Explanation:
when an object's atoms move it causes friction, when friction happens, it heats ups causing thermal energy
<span>A fault slip is the distance of motion, or displacement, along a fault during an earthquake. They can be classified by their relation to the horizontal, for example, if the fault slip happens primarily vertically it is a dip slip.</span>
<span>High photon energy, high frequency, sub-optical wavelength</span>
