Answer: Option B.
Since here the truck is moving on a circular track, it will experience centripetal force.
F(centripetal) = m × acc
or

where r is the radius of the track.
m is the mass of truck
v is the speed of the truck.
Given: v = <span>13 m/s
m = </span><span>1,600 kg
</span>F = 3300 Newton
To find = radius of track=?


r = 81.94 m
Therefore, radius of track is 81.94 m
Answer:
Conservation principles tell us that some<u> quantity, quality, or aspect remains constant through change. </u>
Explanation:
Answer:
Take the numbers and fill them in graph.
Plot time as X and speed as Y and afterward join then like a line graph.
Explanation:
33. The 1.5kg owl is now soaring at 20m/s. What is the owl’s KE?
a. Step 1: Formula <u>½mv²</u>
b. Step 2: Data m = <u>1</u><u>.</u><u>5</u><u> </u><u>kg</u>, v = <u>2</u><u>0</u><u> </u><u>m</u><u>/</u><u>s</u>
c. Step 3: Solve
KE = (1/2)(<u>1</u><u>.</u><u>5</u>)(<u>2</u><u>0</u>)² = <u>3</u><u>0</u><u>0</u><u> </u><u>J</u>
By definition we have that the force for time is equal to the product of the mass for the change in speed.
We have then that
F * (delta t) = m * (delta v)
Clearing the mass
m = (F * (delta t)) / (delta v)
Substituting the values
m = ((3.00) * (4.00)) / (7.50-6.00) = 8
answer
The mass of the moving object is 8Kg