A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the i
1 answer:
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Answer:
Explanation:
Given:
Thickness of the paperweight cube,
apparent depth from one side of the inbuilt paper in the plastic cube,
apparent depth from the other side of the inbuilt paper in the plastic cube,
Now as we know that refractive index is given as:
- Let the real depth form first side of the slab be,
- Then the depth from the second side of the slab will be,
Since refractive index for an amorphous solid is an isotropic quantity so it remains same in all the direction for this plastic.
Now the refractive index:
Answer:
1917723.40119 m/s
Explanation:
m = Mass of deuteron =
k = Boltzmann constant =
T = Temperature =
RMS velocity is given by
The RMS velocity of the deutrons is 1917723.40119 m/s
Answer: 4,438.96m
Explanation:
(kindly find attachment below)
From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.
By using phythagoras theorem
H² = O² + A²
(5.38)² = (3.20)² + B²
28.944 = 10.24 + B²
B² = 28.944 - 10.24
B² = 18.7044
B = √18.7044
B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m
