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Iteru [2.4K]
3 years ago
5

Balance the following redox reaction by inserting the appropriate coefficients. SO4^2- + NH3 = SO3^2- + H2O + N2

Chemistry
2 answers:
Harlamova29_29 [7]3 years ago
6 0

SO₄²⁻  +NH₃  →   SO₃²⁻ + H₂O  +N₂

The  balanced  of  the above  redox reaction   is as below

3SO₄²⁻ + 2NH₃   →  3SO₃²⁻  + 3 H₂O  + N₂


 Explanation

According   to the law of mass conservation the  number  of atoms  in the reactant side  must  be equal to number of atoms in product side.

Inserting coefficient 3 in front of SO₄² , 2  in front  of NH₃, 3 in front  of SO₃²⁻  and 3 in front  of H₂O balance the equation above. This  is  because  the number  of atoms  are equal in both side.

for example there are 2 atoms of N in both side of the reaction.

Simora [160]3 years ago
4 0

Equivalent reaction equation :

3SO₄²⁻ + 2NH₃ ---> 3SO₃²⁻ + N₂ + 3H₂O

<h3>Further explanation</h3>

In equalizing the redox reaction we can use the oxidation number method or half the reaction of the ions

Oxidation number method  :

1. Determine the reducing agent and oxidizing agent

2. Equate the element that experiences a redox reaction

3. Determine the amount of reduction / increase in oxidation number (number of atoms x change in oxidation number)

4. Equate the number of changes in the oxidation number by giving a coefficient

5. equal charge (H + for acidic situations and OH- for alkaline conditions)

6. Balance the H atom with the addition of H₂O

From the reaction :

SO₄²⁻ + NH₃ ---> SO₃²⁻ + H₂O + N₂

1. SO₄²⁻  ---> SO₃²⁻ = reduction (for S : +6 to +4)

NH₃ --->  N₂ = oksidation (for N : -3 to 0)

2. add coefficient  to equate atom N

SO₄²⁻ + 2NH₃ ---> SO₃²⁻ + N₂

3. SO₄²⁻ + 2NH₃ ---> SO₃²⁻ + N₂

  |_+6___2 x 3__+4_|

                  |_-6____6 x 1___0_|

4. giving a coefficient

3SO₄²⁻ + 2NH₃ ---> 3SO₃²⁻ + N₂

5. charge already the same (left = -6, right = -6)

6. Balance the H atom with the addition of H₂O

3SO₄²⁻ + 2NH₃ ---> 3SO₃²⁻ + N₂ + 3H₂O ----> Balance

<h3>Learn more</h3>

an oxidation-reduction reaction

brainly.com/question/2973661

brainly.com/question/2890416

brainly.com/question/2086855

Keywords : Balance, redox, coefficients,Oxidation number, half reaction

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What type of solution has the capacity to dissolve more solute?
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Unsaturated solution

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3 years ago
Several properties of water are shown. Classify each property as a physical property or a chemical property.
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7 0
2 years ago
Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reacti
e-lub [12.9K]

Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

  • Na: 4 moles
  • O₂: 1 mole
  • Na₂O: 2 moles

Being:

  • Na: 23 g/ole
  • O: 16 g/mole

the molar mass of the compounds participating in the reaction is:

  • Na: 23 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • Na₂O: 2*23 g/mole +16 g/mole=  62 g/mole

Then by stoichiometry of the reaction they react and are produced:

  • Na: 4 moles* 23 g/mole= 92 g
  • O₂: 1 mole*32  g/mole= 32 g
  • Na₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}

mass of Na₂O=5.39 g

<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>

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