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topjm [15]
3 years ago
9

If you weighed out 0.38 g of calcium and reacted it with an excess of hcl, how many moles of h2(g) would you expect to produce?

Chemistry
1 answer:
Hitman42 [59]3 years ago
4 0
Answer is: 0,0095 mol of hydrogen gas will be produced in reaction.
Chemical reaction: Ca + 2HCl → CaCl₂ + H₂.
m(Ca) = 0,38 g.
n(H₂) = ?
n(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 0,38 g ÷ 40 g/mol
n(Ca) = 0,0095 mol.
from reaction: n(Ca) : n(H₂) = 1 : 1.
n(H₂) = n(Ca) = 0,0095 mol.
n - amount of substance.
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Answer:

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Explanation:

We need to convert g of Cl 2 to moles of Cl. First we divide 130 gCl2  by the molar mass (70.90 gCl2/mol) to find out how many moles of Cl2 do we have.

130 gCl2 x \frac{1 mol Cl2 }{70.90 gCl2} = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

1.83 molCl2 x \frac{2 molCl}{1 molCl2} = 3.67 molCl

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3 years ago
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Answer:

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Answer:

See Explanation ( = same answer for earlier question)

Explanation:

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