Answer:
338N
Explanation:
Use the formula 
f is the frequency, T the string tension, M the mass, and L the length
convert units to seconds, kilograms, meters
now solve for T
sqrt(T/.005) = 65*4 = 260
T = 338N
Well, you haven't given us much of a choice of graphs to pick from, have you.
If a sample of an ideal gas is held at constant temperature, then
its pressure and volume are inversely proportional ... the harder
you squeeze it, the smaller the volume gets, and less squeeze
produces more volume.
Actually, the product of (pressure) x (volume) is always the
same number.
The graph of that relationship is all in the first quadrant.
It starts out very high right next to the y-axis, then drops down
toward the x-axis while curving to the right and becoming horizontal,
and ends up trying to get closer and closer to the x-axis but never
actually becoming zero.
What is newton's second law of motion?Also give example.
<u>Definition</u>:-
Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force. ie., <u>F=ma</u>.
<u>Examples:-</u>
- When you are kicking a ball, you are increasing the speed by applying force to it. Therefore,it accelerates.
- If you use the same force to push a truck and push a car, the car will have more acceleration than the truck.
Derivation:-
For a body of mass 'm' , whose velocity changes from u to v in time t, when Force 'F' is applied.
=>Force∝Change in momentum/Time
=>F∝mv-mu/t
=>F∝m(v-u)/t
=>F∝ma
=>F=kma(a=v-u/t)
=>F=ma(Since k=constant=1)
The right answer for the question that is being asked and shown above is that: "<span>B: 156 kPa ." </span>Marshall determines that a gas has a gage pressure of 276 kPa whats the absolute pressure of this gas <span>B: 156 kPa </span>
Answer:
(a) V1 = 8990.00 V
V2 = 8960.13 V
Explanation:
Parameters given:
q =3 mC
k = 8.99 * 10⁹ Nm²/C²
x1 = 3 m
x2 = 3.01 m
Electric potential is given as:
V = kq/r
Where
k = Coulombs constant
q = charge
r = distance
Potential at x1 is:
V1 = (8.99 * 10⁹ * 0.000003)/(3)
V1 = 8990.00V
Potential at x2 is:
V2 = (8.99 * 10⁹ * 0.003)/(3.01)
V2 = 8960.13 V
