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Rainbow [258]
3 years ago
9

Natural history research involves ____ unobsevable and unrepeatable past events.

Physics
1 answer:
Tanzania [10]3 years ago
4 0
B verifying is the answer
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A motorcycle is traveling with a velocity of 4 m/s and has a mass of 112 kg
Zarrin [17]

Answer: 896J

Explanation:

Given that

Mass of motorcycle = 112kg

kinetic energy = ?

velocity of the motorcycle = 4m/s

Since kinetic energy is the energy possessed by a moving object, and it depends on the mass (m) of the object and the velocity (v) by which it moves. Therefore, the motorcycle has kinetic energy

i.e K.E = 1/2mv^2

KE = 1/2 x 112kg x (4m/s)^2

KE = 0.5 x 112 x 16

KE = 896J

Thus, the motorcycle has 896 joules of kinetic energy.

8 0
3 years ago
A car is designed to get its energy from a rotating
nydimaria [60]

Answer:

(a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power P= 15.0 hp = 15.0\times746=11190 watt

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}mr^2

Put the value into the formula

I=\dfrac{1}{2}\times475\times(1.50)^2

I=534.375\ kg m^2

(a). We need to calculate the kinetic energy stored in  the fly wheel

Using formula of K.E

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2

K.E=46880620.9\ J

K.E =46.88\times10^{6}\ J

K.E =46.88\ MJ

(b). We need to calculate the length of time the car could run before the flywheel  would have to be brought backup to speed

Using formula of time

t=\dfrac{46.88\times10^{6}}{11190}

t=4189.45\ sec

t=1.163\ hours

Hence, (a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

3 0
3 years ago
Tammy leaves the office, drives 26 km due
fredd [130]

Answer:

72.98 km

Explanation:

Her displacement is simply the distance from her final position to her initial position.

Now, I've drawn and attached a triangle diagram to depict this her movement.

Point O is her initial starting point.

Point A is the first point she gets to after travelling north while point B is the final point after travelling north east.

From the triangle, the displacement will be the distance OB which is denoted by x and can be solved from cosine rule.

Thus;

x² = 62² + 26² - 2(62 × 26)cos 120

x² = 4520 + 806

x² = 5326

x = √5326

x = 72.98 km

4 0
2 years ago
Practice Exercises Name: : Billy-Joe stands on the Talahatchee Bridge kicking stones into the water below a) If Billy-Joe kicks
babymother [125]

Answer:

a) The answer is 11,7m

b) The time it takes to fall will be shorter

Explanation:

We will use the next semi-parabolic movement equations

H=Hi+Viy*t+1/2*g*t

X=Xi+Vx*t

Where g(gravity acceleration)=9,81m/s^2

Also Xi, Hi and Viy are zero, as the stones Billy-Jones is kicking stay still before he moves them, so we take that point as the reference point

The first we must do is to find how much time the stones take to fall, this way:

t=(5.40m)/(3.50m/s)

Then t=1,54s

After that we need to replace t to find H, this way

H=(1/2)*(9,81m/s^2)*(1,54s)^2

Then H=11,7m

b) The stones will fall faster as the stones will be kicked harder, it will cause the stones move faster, it means, more horizontal velocity. In order to see it better we could assume the actual velocity is two times more than it is, so it will give us half of the time, this way:

t=(5,40m)/(2*3,50m/s)

Then, t=0,77

4 0
3 years ago
A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
Read 2 more answers
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