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Gnom [1K]
3 years ago
6

A large fish hangs from a spring balance supported from the roof of an elevator. If the elevator has an upward acceleration of 2

.45 m/s
2 and the balance reads 60.0 N, what is the true weight of the fish?
Physics
1 answer:
inn [45]3 years ago
6 0

Answer:

Original Weight = 48 N

Explanation:

When an object hanging from the roof of an elevator and the elevator moves upward with a certain acceleration say a, then the observe weight is always greater than the actual weight.

And when elevator moves downward direction with acceleration a, then the observe weight is always lesser than the actual weight.

Given data:

a = 2.45 m/s²

Balance reading = Tension = T = 60 N

As elevator moves upward,

So,

               T = m(g + a)

         60 N = m(9.81 + 2.45)

               m = 60/12.26

               m = 4.89 kg

This is the original mass of the hanging fish.

We know that

                Weight = W = mg

                                W = 4.89 × 9.81

                                W = 48 N

       

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For this case, the first thing you should know is that the length of a football field is around 100 meters.

We must then look for a measure close to this value.

We have the following unit conversion:

1 meter = 10 decimeters

Applying the conversion we have:

(1000 dm)*(\frac{1}{10} \frac{m}{dm}) = 100 m

Therefore, the measure closest to a soccer field is:

1000 dm

Answer:

The length of a football field is closest to:

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Which one of the following statements is false?
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Answer:

d) False. If the angular momentum is zero, it implies in electro without turning, which would create a collapse towards the nucleus, so in both models the moment must be different from zero

Explanation:

Affirmations

a) true. The orbits are accurate in the Bohr model and probabilistic in quantum mechanics

b) True. If both give the same results and use the same quantum number (n)

c) True. If in angular momentum it is quantized, in the Bohr model too but it does not justify it

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3 years ago
There is a 250-m-high cliff at half dome in yosemite national park in california. suppose a boulder breaks loose from the top of
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Part A. For this part, we use two equations for linear motion:

<span>y = y0 + v0 t + 0.5 g t^2                   ---> 1</span>

<span>vf = v0 + g t                                         ---> 2</span>

First we solve for t using equation 1: y0 = 0 (initial point at top), y = 250 m, v0 = 0 (at rest)

250 = 0.5 (9.8) t^2

t = 7.143 s

Now we solve for final velocity vf using equation 2:

vf = g t

vf = 9.8 (7.143)

vf = 70 m/s

 

Part B. First we solve for the time it takes for the sound to reach the tourist.

t(sound) = 250 / 335 = 0.746 s

Therefore the total time would be:

t = 0.746 s + 0.300 s

t = 1.05 s

 

<span>Hence there is enough time for the tourist to get out before the boulder hits him.</span>

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3 years ago
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While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p
algol13

Answer:

True

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In Massachusetts it's illegal to drive while texting or on your phone.

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A)
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Answer:

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So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.

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So if we go from A to B, the displacement is simply the line AB.

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displacement = √( (AB)^2 + (BC)^2)

Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.

Those are:

A to B  ( or B to A)

B to C  (or C to B)

C to D  (or D to C)

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