1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnom [1K]
3 years ago
6

A large fish hangs from a spring balance supported from the roof of an elevator. If the elevator has an upward acceleration of 2

.45 m/s
2 and the balance reads 60.0 N, what is the true weight of the fish?
Physics
1 answer:
inn [45]3 years ago
6 0

Answer:

Original Weight = 48 N

Explanation:

When an object hanging from the roof of an elevator and the elevator moves upward with a certain acceleration say a, then the observe weight is always greater than the actual weight.

And when elevator moves downward direction with acceleration a, then the observe weight is always lesser than the actual weight.

Given data:

a = 2.45 m/s²

Balance reading = Tension = T = 60 N

As elevator moves upward,

So,

               T = m(g + a)

         60 N = m(9.81 + 2.45)

               m = 60/12.26

               m = 4.89 kg

This is the original mass of the hanging fish.

We know that

                Weight = W = mg

                                W = 4.89 × 9.81

                                W = 48 N

       

You might be interested in
A child blows a leaf from rest straight up in the air. The leaf has a constant upward acceleration of magnitude 1.0\,\dfrac{\tex
Novosadov [1.4K]

Answer:

Explanation:

Given

Acceleration a = 1.0m/s²

Displacement S = 1.0m

Required

Time t taken by the leaf to displace

Using the equation of motion

S = ut+1/2at²

Substitute

1.0 = 0+1/2(1)t²

1 = t²/2

Cross multiply

t² = 2

t = ±√2

t = 1.41secs

It takes the leaf to 1.41s to displace by 1m upward

6 0
4 years ago
Two blocks of masses 20 kg and 8.0 kg are connected togetherby
Dmitry [639]

Answer:

The tension is 14 N

Explanation:

For this problem we have to use newton's law, so:

F=m*a

The second string is connected to the mass of 8 kg, but the mass of 8 kg is connected to the mass of 20kg, so we can say that the second string is handling the two masses. so:

F=28kg*0.5\frac{m}{s^2}=14N

3 0
3 years ago
Grace drives her car 168 km in 2 hours. What is her average speed in kilometers per hour?
wlad13 [49]

Answer:

84kliometers

Explanation:

divide one hundred and sixty eight kilo meters by two hours

5 0
3 years ago
The table below shows the height of some horse fossils.
choli [55]

Answer:

Y W Z X, B

Explanation:

It wants you to figure out the correct order starting from oldest to newest.

7 0
3 years ago
Read 2 more answers
You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Y
Dvinal [7]

Answer:

380697.33\ \text{N/m}

0.138\ \text{m}

Explanation:

m = Mass rocket = 1070 kg

v = Velocity of rocket = 3.75 m/s

a = Acceleration of rocket = 5g

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The energy balance of the system is given by

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}

The force balance of the system is given by

ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}

The distance the spring must be compressed is 0.138\ \text{m}

k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}

The force constant of the spring is 380697.33\ \text{N/m}.

4 0
3 years ago
Other questions:
  • Which are examples of transverse waves? Check all that apply. earthquake P-waves earthquake S-waves radio waves sound visible li
    8·2 answers
  • Two loops of wire are arranged so that a changing current in one, the primary, will induce a current in the other, the secondary
    13·2 answers
  • How much time is needed to produce 900 Joules of work if 120 watts of power is used?
    5·1 answer
  • A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f
    6·1 answer
  • A plant root i an example of ___________
    10·1 answer
  • A hiker throws a ball at an angle of 21.0° above the horizontal from a hill 21.0 m high. The hiker’s height is 1.750 m. The magn
    15·1 answer
  • 3 points
    5·1 answer
  • What is this please please please help me out
    13·2 answers
  • I need some help with this.
    8·1 answer
  • Set local ground level to 700 ft, and record the inches of mercury.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!