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Gnom [1K]
3 years ago
6

A large fish hangs from a spring balance supported from the roof of an elevator. If the elevator has an upward acceleration of 2

.45 m/s
2 and the balance reads 60.0 N, what is the true weight of the fish?
Physics
1 answer:
inn [45]3 years ago
6 0

Answer:

Original Weight = 48 N

Explanation:

When an object hanging from the roof of an elevator and the elevator moves upward with a certain acceleration say a, then the observe weight is always greater than the actual weight.

And when elevator moves downward direction with acceleration a, then the observe weight is always lesser than the actual weight.

Given data:

a = 2.45 m/s²

Balance reading = Tension = T = 60 N

As elevator moves upward,

So,

               T = m(g + a)

         60 N = m(9.81 + 2.45)

               m = 60/12.26

               m = 4.89 kg

This is the original mass of the hanging fish.

We know that

                Weight = W = mg

                                W = 4.89 × 9.81

                                W = 48 N

       

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Talja [164]

Well we can just use F=ma. The force is 10N, the mass is 50 kg, solve for a. Well since we kg and N, no conversion is necessary. So just plugging in the numbers, we get

10N = 50 kg · a

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The s^2 and 50 kg you multiply

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The kg's cancel and 10/50 is 1/5

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Please see the link below for more information

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