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lana [24]
3 years ago
13

A car is designed to get its energy from a rotating

Physics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

(a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power P= 15.0 hp = 15.0\times746=11190 watt

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}mr^2

Put the value into the formula

I=\dfrac{1}{2}\times475\times(1.50)^2

I=534.375\ kg m^2

(a). We need to calculate the kinetic energy stored in  the fly wheel

Using formula of K.E

K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2

K.E=46880620.9\ J

K.E =46.88\times10^{6}\ J

K.E =46.88\ MJ

(b). We need to calculate the length of time the car could run before the flywheel  would have to be brought backup to speed

Using formula of time

t=\dfrac{46.88\times10^{6}}{11190}

t=4189.45\ sec

t=1.163\ hours

Hence, (a). The kinetic energy stored in  the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

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Recall the force applied to a spring and its extension/compression:

F = kΔx

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x = 0.7 m

x₀ = 0.4 m

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Substitute and solve for k:

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3 years ago
A canon is tilled back 30.0 degrees and shoots a cannon ball at 155 m/s. What is the
Umnica [9.8K]

Answer:

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

Explanation:

the cannon is fired at an angle 30 o to the horizonatal with a speed of 155 m/s

highest point that the cannon ball reaches?

H_{max}=\frac{V^2\sin ^2 \theta}{2g}

g = 9.8m/s2

= \frac{(115^2)(\sin 30)^2}{2\times 9,8} \\\\= 168.7m

Therefore, highest point that the cannon ball reaches is 168.7m

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Describe motion of the sun
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Answer:

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A pitcher can throw a baseball at about 90 miles/hour (about 39.6 m/s). What is the ratio of the kinetic energy to the rest ener
tester [92]

Answer:

8.71*10^{-15}

Explanation:

The rest energy is the energy associated with the base ball at zero velocity which is expressed as

Rest energy=mc^{2}\\

Note: the speed C is the speed of light which is expressed as 3*10^8

while the kinetic energy is the energy associated with the ball during its motion and is expressed as

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the ratio can be expressed as

\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}mv^{2} }{mc^{2}}\\since V=39.6m/s\\C=3*10^{8}m/s\\\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}39.6^{2} }{(3*10^8)^{2}} \\\frac{Kinetic Energy}{Rest Energy}=\frac{784.08}{9*10^{16}} \\\frac{Kinetic Energy}{Rest Energy}=8.71*10^{-15}

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4 years ago
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