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Makovka662 [10]
3 years ago
6

A car is driving away from a crosswalk. The formula d = t 2 + 2 t expresses the car's distance from the crosswalk in feet, d , i

n terms of the number of seconds, t , since the car started moving. Suppose t varies from t = 2 to t = 5 . Does the car travel at a constant speed over this interval of time? Correct What is the car's average speed over this interval of time? 10 Incorrect feet per second Suppose t varies from t = 1.8 to t = 2.1 . Does the car travel at a constant speed over this interval of time? Correct What is the car's average speed over this interval of time?
Physics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

1) No, the car does not travel at constant speed.

2) V = 9 ft/s

3) No, the car does not travel at constant speed.

4) V = 5.9 ft/s

Explanation:

In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:

V(t) = 2*t + 2   Since the speed depends on time, the speed is not constant at any time.

For the average speed we evaluate the formula for t=2 and t=5:

d(2) = 8 ft     and      d(5) = 35 ft

V_{2-5}=\frac{d(5)-d(2)}{5-2}=9 ft/s

Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:

d(1.8) = 6.84 ft     and      d(2.1) = 8.61 ft

V_{1.8-2.1}=\frac{d(2.1)-d(1.8)}{2.1-1.8}=5.9 ft/s

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Vitek1552 [10]

Answer:

v = 54m/s

Explanation:

a =  \frac{v - u}{t}

a = 7m/s²

u = 12m/s

t = 6s

7 = (v-12)/6

v - 12 = 42

v = 54m/s

(Correct me if i am wrong)

3 0
3 years ago
What is emotional strength?​
Ugo [173]

Answer:

Emotional strength is a person's ability to deal with challenges (any kind) and how they can bounce back on that certain situation.

I hope this helps you.

4 0
3 years ago
In an experiment, 1 mol of propane is burned to form carbon dioxide and water.
Natalija [7]

Answer:

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5 0
3 years ago
find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²
Ierofanga [76]

Answer:

T_{m } = 4.86 s

T_{e} = 1.98 s

Explanation:

<u><em>Given:</em></u>

Length = l = 1 m

Acceleration due to gravity of moon = g_{m} = 1.67 m/s²

Acceleration due to gravity of Earth = g_{e} = 10 m/s²

<u><em>Required:</em></u>

Time period = T = ?

<u><em>Formula:</em></u>

T = 2π \sqrt{\frac{l}{g} }

<u><em>Solution:</em></u>

<u>For moon</u>

<em>Putting the givens,</em>

T = 2(3.14) \sqrt{\frac{1}{1.67} }

T = 6.3 \sqrt{0.6}

T = 6.3 × 0.77

T = 4.86 sec

<u>For Earth,</u>

<em>Putting the givens</em>

T = 2π \sqrt{\frac{1}{10} }

T = 2(3.14) \sqrt{0.1}

T = 6.3 × 0.32

T = 1.98 sec

3 0
3 years ago
The density of water is 1.00 g/cm3. What is its density in kg/m3?
r-ruslan [8.4K]
1 g = 1 ÷ 1000 kg
= 0.001 kg

1 cm³ = 1 ÷ 100 ÷ 100 ÷ 100 m³
= 0.000001 m³

1 g/cm³ = 1 g / 1 cm³
= 0.001 kg / 0.000001 m³
= 1000 kg/m³

The density is 1000 kg/m³.
3 0
3 years ago
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