All categories

2 years ago

Jenna can run 9 km in 1 hour. If she runs at that speed for 30 minutes, how far will she go? *

Physics

1 answer:

crimeas [40]2 years ago

5 0

Answer:

4.5 km / 450 m

Explanation:

1 hour = 9 km

or, 60 min = 9km

or, 60/2 min = 9/2 km

■ 30 min = 4.5 km

heart plzz and brainliest answer as well

You might be interested in

H e l p.. I have no idea what any of this is, what is the first step of the hydrogen fusion process

klasskru [66]

The answer to this question is the first choice. In the hydrogen fusion process, the first step involves the collision of two protons to emit an antielectron and a neutrino. Only the first choice of
1_1H + 1_1H →2_1H + e^+ + v + energy
reflects this process. A hydrogen ion with a mass of one and number protons of 1 means a proton.

4 0

2 years ago

Read 2 more answers

Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitu

grin007 [14]

Answer:

Explanation:

d = vo*t + ½*g*t²

d = 3*3 + ½*10*3²

d = 9 + 45

d = 54 m

entonces el objeto tiene 54 m de desplazamiento

7 0

2 years ago

Tammy is a forensic investigator examining a body at a crime scene. She notes that the body is stiff but still flexible. What do

wlad13 [49]

I may be wrong but does it mean it was revent? because i know shortly after someone dies your body becomes fully stiff so maybe it was recent and it's in the process off stiffening up

8 0

2 years ago

The area around a charged object that can exert a force on other charged objects is an electric ___

Ymorist [56]

Answer is:

Electric field.

8 0

2 years ago

At a meeting of physics teacher in Montana, the teachers were asked to calculate where a flour sack would land if dropped from a

Harlamova29_29 [7]

At a distance of 469.2 m from the original point below the airplane.

Explanation:

First of all, we have to calculate the time it takes for the sack to reach the ground.

To do so, we just analyze its vertical motion, which is a free-fall motion, so we can use the suvat equation:

$s=ut+\frac{1}{2}at^2$

where, taking downward as positive direction:

s = 300 m is the vertical displacement

u = 0 is the initial vertical velocity

t is the time

$a=g=9.8 m/s^2$ is the acceleration of gravity

Solving for t, we find the it takes for the sack to reach the ground:

$t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(300)}{9.8}}=7.82 s$

Now we analyze the horizontal motion. The horizontal velocity of the pack is constant (since there are no forces along the horizontal direction) and equal to the initial speed of the airplane, so:

$v_x = 60 m/s$