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IgorLugansk [536]
3 years ago
8

A car traveling at 10 m/s speeds up to 20 m/s in 3 seconds. determine the acceleration of the car

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

66m/s

Explanation:

because 10 meters/per second is going to be 22 mph/35 km, and 20m/s is 44 mph/70 km and in 3 seconds it would boost its mph/km(m/s) to 66 only because from 22 mph to 44 mph is 22 but 44/22 = 22, however you have top multiply that by 3 seconds which will coem out to 66 m/s, mph, km.

astra-53 [7]3 years ago
4 0

Answer: 3.33m/s²

Explanation:

Acceleration = rate of change in velocity with time

Acceleration = change in velocity / time

Initial velocity (u) = 10 m/s

Final velocity (v) = 20m/s

time (t) = 3s

a = V - U / t

a = (20 - 10) / 3

a = 10 / 3 = 3.33m/s²

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A man takes 20 seconds to climb 5m up a ladder. He weighs 720N. Calculate the power he must deliver to do this.
Inessa05 [86]

Answer:

180 W

Explanation:

The work done by the man against gravity is equal to its gain in gravitational potential energy:

W=mg\Delta h

where

(mg) = 720 N is the weight of the man

\Delta h= 5 m is the change in height

Substituting,

W=(720)(5)=3600 J

The power he must deliver is given by

P=\frac{W}{t}

where

W = 3600 J

t = 20 s is the time taken

Substituting,

P=\frac{3600}{20}=180 W

3 0
3 years ago
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg
ahrayia [7]

Answer:

The final components of velocity of the composite object is 3.33 m/s.

Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

R² = 303.858

R = √303.858

R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

P₁(x) + P₂(y) = Pf

R = Pf

R = v(m₁ + m₂)

17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s

Therefore, the final components of velocity of the composite object is 3.33 m/s.

8 0
3 years ago
A person jogs 4.0 km in 32 minutes, then 2.0 km in 22 minutes, and finally 1.0 km in 16 minutes. What is the jogger's average sp
kupik [55]

Answer:

22

Explanation:

i did it before

7 0
4 years ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23
Burka [1]

Answer:

a) v(2) = 3.9\,\frac{m}{s}, b) v(4) = -15.7\,\frac{m}{s}

Explanation:

a) The equation for vertical velocity is obtained by deriving the function with respect to time:

v(t) = 23.5 -9.8\cdot t

The velocities at given instants are, respectivelly:

v(2) = 3.9\,\frac{m}{s}

v(4) = -15.7\,\frac{m}{s}

8 0
3 years ago
Someone help I'm stuck on question 8 and 12
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Sippen lein an hr later is theanswer to both 

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