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IgorLugansk [536]
3 years ago
8

A car traveling at 10 m/s speeds up to 20 m/s in 3 seconds. determine the acceleration of the car

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

66m/s

Explanation:

because 10 meters/per second is going to be 22 mph/35 km, and 20m/s is 44 mph/70 km and in 3 seconds it would boost its mph/km(m/s) to 66 only because from 22 mph to 44 mph is 22 but 44/22 = 22, however you have top multiply that by 3 seconds which will coem out to 66 m/s, mph, km.

astra-53 [7]3 years ago
4 0

Answer: 3.33m/s²

Explanation:

Acceleration = rate of change in velocity with time

Acceleration = change in velocity / time

Initial velocity (u) = 10 m/s

Final velocity (v) = 20m/s

time (t) = 3s

a = V - U / t

a = (20 - 10) / 3

a = 10 / 3 = 3.33m/s²

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A boiler is being used to heat water. The graph shows the temperature of
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Answer:

a. Liquid state

b. At point R. The physical state of water at its boiling point temperature of 100 degree Celsius will be both liquid state as well as gaseous state.

c. at 110 degrees it is in gaseous state

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3 years ago
2. What is the mass of an object if it accelerates at 3 m/s2 and has a force of 1 N?
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Answer:

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2 years ago
Aunt Matilda goes to a well and throws a penny straight down the well at 3.0 m/s. She hears a splash after 0.5 seconds. How deep
nevsk [136]

Answer : The correct option is (d) 2.73 m

Explanation :

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2

where,

s = distance or height = ?

u = initial velocity  = 3.0 m/s

t = time = 0.5 s

a = acceleration due to gravity = 9.8m/s^2

Now put all the given values in the above equation, we get:

s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2

s=2.73m

Therefore, the correct option is (d) 2.73 m

8 0
3 years ago
When the pressure at the bottom of a submerged object is greater than the pressure at the top of submerged object, buoyant force
ELEN [110]
The answer would most like be true!
4 0
3 years ago
Read 2 more answers
What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 7400 N
bezimeni [28]

Answer: a = 1.32 * 10^18m/s² due north

Explanation: The magnitude of the force required to move the electron is given as

F = ma

The force exerted on the charge by the electric field of intensity (E) is given by

F = Eq

Thus

Eq = ma

a = E * q/ m

Where a = acceleration of charge

E = strength of electric field = 7400N/c

q = magnitude of electronic charge = 1.609 * 10^-6c

m = mass of an electronic charge = 9.109 * 10^-31kg

a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31

a = 11906.6 * 10^-16 / 9.019 * 10^-31

a = 1.19 * 10^-12 / 9.019 * 10^-31

a = 0.132 * 10^19

a = 1.32 * 10^18m/s²

As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)

5 0
3 years ago
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