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4 years ago

A 10cm spring is hung from a clamp stand. With 1N of force it measures 12.2cm long and with 3N of force it measures 16.4cm long.

Physics

1 answer:

solmaris [256]4 years ago

7 0

Answer:

0.48 N/cm

Explanation:

The original length is 10cm so with a force of 10cm, the extension will be 12.2-10=2.2 cm when force of 1N is exerted. Similarly, with a force of 3N, the extension is 16.4-10=6.4cm

The slope will be given by change in force/ change in extension and this is equivalent to the stiffness.

Change in force is 3-1=2 N

Change in exgension is 6.4-2.2=4.2 cm

The slope will be 2/4.2=0.4761904761904 N/cm

Rounded off, the slope is 0.48 N/cm and this is the stiffness of the spring.

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gogolik [260]

Refer to the diagram shown below.

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When we compare magnitudes of u for the door, we find that
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Answer:
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5 0

3 years ago

A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie

Scilla [17]

Answer:

Induced current, I = 0.5 A

Explanation:

It is given that,

number of turns, N = 20

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Final magnetic field, $B_f=6\ T$

Time taken, t = 2 s

Resistance of the coil, R = 0.4 ohms

We know that due to change in magnetic field and emf will be induced in the coil. Its formula is given by :

$\epsilon=\dfrac{-d\phi}{dt}$

Where

$\phi=BA$

$\epsilon=\dfrac{-d(NBA)}{dt}$

$\epsilon=NA\dfrac{B_f-B_i}{t}$

$\epsilon=20\times 0.005\times \dfrac{6-2}{2}$

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Let I is the induced current in the wire. It can be calculated using Ohm's law as :

$\epsilon=I\times R$

$I=\dfrac{\epsilon}{R}$

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I = 0.5 A

So, the magnitude of the induced current in the coil is 0.5 A. Hence, this is the required solution.

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3 years ago

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