Answer:
chromatography
Explanation:
Chromatography is one of the powerful technique that is used to separate the mixed components of liquid or the gas mixtures.
In this technique the separation of the mixture by passing the mixture in some solution or some suspension through the medium where the components are made to move at some different rates.
The basic idea in this experiment is that the mixture sample is in mobile phase and it is forced either by pumping or by gravity or by capillary action through the stationary phase to separate the mixture.
Molecular formulas:
- CH₂O;
- C₂H₄O₂;
- C₆H₁₂O₆.
<h3>Explanation</h3>
The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,
- for each C atom, there are
- two H atoms, and
- one O atom.
The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.
It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is
.
- CH₂O- 30.0 g/mol;
- C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
- C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.
It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.
It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.
It takes
sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.
There the potential difference is -0. 553 keQ/R.
What is Electric potential ?
The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
Electric potential at point 0,
V1 = ke Q/R
Electric potential at x= 2R
V2= keQ/ root5. R
Therefore potential difference is
dV = V2 - V1
Putting the values we get ,
dV = -0. 553 keQ/R
To learn more about electric potential click on the link below:
brainly.com/question/23980243
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Answer:
-34.5 W
Explanation:
rate of heat transfer = Stefan-Boltzmann constant x emissivity x surface area x temperature^4
